CAIE FP1 2002 November — Question 11 EITHER

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2002
SessionNovember
PaperDownload PDF ↗
TopicInvariant lines and eigenvalues and vectors
TypeProve eigenvalue/eigenvector properties
DifficultyStandard +0.8 This question combines theoretical proof (showing eigenvector properties under matrix operations) with computational work (finding eigenvalues/eigenvectors of 3×3 matrices). The proofs are straightforward applications of definitions, but finding eigenvalues requires solving a cubic characteristic equation and then finding corresponding eigenvectors through row reduction. The B² part adds complexity as students must either compute B² first or use the proven relationship. This is moderately challenging for Further Maths students but follows standard techniques.
Spec4.03a Matrix language: terminology and notation4.03b Matrix operations: addition, multiplication, scalar

The vector \(\mathbf { e }\) is an eigenvector of the square matrix \(\mathbf { G }\). Show that
  1. \(\mathbf { e }\) is an eigenvector of \(\mathbf { G } + k \mathbf { I }\), where \(k\) is a scalar and \(\mathbf { I }\) is an identity matrix,
  2. \(\mathbf { e }\) is an cigenvector of \(\mathbf { G } ^ { 2 }\). Find the eigenvalues, and corresponding eigenvectors, of the matrices \(\mathbf { A }\) and \(\mathbf { B } ^ { 2 }\), where $$\mathbf { A } = \left( \begin{array} { r r r } 3 & - 3 & 0 \\ 1 & 0 & 1 \\ - 1 & 3 & 2 \end{array} \right) \quad \text { and } \quad \mathbf { B } = \left( \begin{array} { r r r } - 5 & - 3 & 0 \\ 1 & - 8 & 1 \\ - 1 & 3 & - 6 \end{array} \right)$$

The vector $\mathbf { e }$ is an eigenvector of the square matrix $\mathbf { G }$. Show that\\
(i) $\mathbf { e }$ is an eigenvector of $\mathbf { G } + k \mathbf { I }$, where $k$ is a scalar and $\mathbf { I }$ is an identity matrix,\\
(ii) $\mathbf { e }$ is an cigenvector of $\mathbf { G } ^ { 2 }$.

Find the eigenvalues, and corresponding eigenvectors, of the matrices $\mathbf { A }$ and $\mathbf { B } ^ { 2 }$, where

$$\mathbf { A } = \left( \begin{array} { r r r } 
3 & - 3 & 0 \\
1 & 0 & 1 \\
- 1 & 3 & 2
\end{array} \right) \quad \text { and } \quad \mathbf { B } = \left( \begin{array} { r r r } 
- 5 & - 3 & 0 \\
1 & - 8 & 1 \\
- 1 & 3 & - 6
\end{array} \right)$$

\hfill \mbox{\textit{CAIE FP1 2002 Q11 EITHER}}