CAIE FP1 2011 June — Question 4 8 marks

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2011
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicImplicit equations and differentiation
TypeFind second derivative d²y/dx²
DifficultyStandard +0.8 This is a Further Maths implicit differentiation question requiring both first and second derivatives. While the first derivative is straightforward product rule application, finding d²y/dx² implicitly requires careful differentiation of dy/dx (which itself contains dy/dx terms), then substitution of known values. This is more demanding than standard C3/C4 implicit differentiation and requires systematic algebraic manipulation, placing it moderately above average difficulty.
Spec1.07s Parametric and implicit differentiation

4 The curve \(C\) has equation $$2 x y ^ { 2 } + 3 x ^ { 2 } y = 1$$ Show that, at the point \(A ( - 1,1 )\) on \(C , \frac { \mathrm {~d} y } { \mathrm {~d} x } = - 4\). Find the value of \(\frac { \mathrm { d } ^ { 2 } y } { \mathrm {~d} x ^ { 2 } }\) at \(A\).

Question 4:
AnswerMarks Guidance
Working/AnswerMarks Guidance
\(2y^2 + 4xyy' + 6xy + 3x^2y' = 0\)B1B1 Differentiates with respect to \(x\)
\(2 - 4y' - 6 + 3y' = 0 \Rightarrow y' = -4\) (AG)B1 Substitutes \((-1, 1)\)
\(4yy'' + (4y + 4xy')y' + 4xyy'' + 6y + 6xy' + 6xy' + 3x^2y'' = 0\)B1B1 Differentiates again
\(-16 - 80 - 4y'' + 6 + 24 + 24 + 3y'' = 0\)M1 Substitutes \((-1,1)\) and \(y'=-4\)
\(\Rightarrow y'' = -42\)A1
# Question 4:

| Working/Answer | Marks | Guidance |
|---|---|---|
| $2y^2 + 4xyy' + 6xy + 3x^2y' = 0$ | B1B1 | Differentiates with respect to $x$ |
| $2 - 4y' - 6 + 3y' = 0 \Rightarrow y' = -4$ (AG) | B1 | Substitutes $(-1, 1)$ |
| $4yy'' + (4y + 4xy')y' + 4xyy'' + 6y + 6xy' + 6xy' + 3x^2y'' = 0$ | B1B1 | Differentiates again |
| $-16 - 80 - 4y'' + 6 + 24 + 24 + 3y'' = 0$ | M1 | Substitutes $(-1,1)$ and $y'=-4$ |
| $\Rightarrow y'' = -42$ | A1 | |

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4 The curve $C$ has equation

$$2 x y ^ { 2 } + 3 x ^ { 2 } y = 1$$

Show that, at the point $A ( - 1,1 )$ on $C , \frac { \mathrm {~d} y } { \mathrm {~d} x } = - 4$.

Find the value of $\frac { \mathrm { d } ^ { 2 } y } { \mathrm {~d} x ^ { 2 } }$ at $A$.

\hfill \mbox{\textit{CAIE FP1 2011 Q4 [8]}}