OCR MEI C2 2006 January — Question 6 4 marks

Exam BoardOCR MEI
ModuleC2 (Core Mathematics 2)
Year2006
SessionJanuary
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTangents, normals and gradients
TypeDetermine nature of stationary points
DifficultyModerate -0.3 This question requires finding a second derivative by differentiating a polynomial (straightforward), then applying standard criteria for stationary points (dy/dx = 0) and inflection points (d²y/dx² = 0). While it involves two concepts together, both are routine C2-level techniques with no problem-solving insight required, making it slightly easier than average.
Spec1.07d Second derivatives: d^2y/dx^2 notation1.07e Second derivative: as rate of change of gradient1.07n Stationary points: find maxima, minima using derivatives1.07p Points of inflection: using second derivative

6 A curve has gradient given by \(\frac { \mathrm { d } y } { \mathrm {~d} x } = x ^ { 2 } - 6 x + 9\). Find \(\frac { \mathrm { d } ^ { 2 } y } { \mathrm {~d} x ^ { 2 } }\).
Show that the curve has a stationary point of inflection when \(x = 3\).

AnswerMarks Guidance
\(y'' = 2x - 6\)B1
\(y'' = 0\) at \(x = 3\)B1
\(y' = 0\) at \(x = 3\)B1
showing \(y'\) does not change signE1 or that \(y''\) changes sign
$y'' = 2x - 6$ | B1 |
$y'' = 0$ at $x = 3$ | B1 |
$y' = 0$ at $x = 3$ | B1 |
showing $y'$ does not change sign | E1 | or that $y''$ changes sign | 4 marks total
6 A curve has gradient given by $\frac { \mathrm { d } y } { \mathrm {~d} x } = x ^ { 2 } - 6 x + 9$. Find $\frac { \mathrm { d } ^ { 2 } y } { \mathrm {~d} x ^ { 2 } }$.\\
Show that the curve has a stationary point of inflection when $x = 3$.

\hfill \mbox{\textit{OCR MEI C2 2006 Q6 [4]}}