OCR MEI C2 2006 January — Question 3 3 marks

Exam BoardOCR MEI
ModuleC2 (Core Mathematics 2)
Year2006
SessionJanuary
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTrigonometric equations in context
TypeExact value from special triangle
DifficultyEasy -1.8 This is a straightforward geometric proof requiring only basic trigonometry (SOHCAHTOA) applied to a standard 30-60-90 triangle. Students need to recognize or construct the equilateral triangle setup and apply the sine ratio directly—pure recall with minimal problem-solving, significantly easier than average A-level questions.
Spec1.01a Proof: structure of mathematical proof and logical steps1.05g Exact trigonometric values: for standard angles
3 Fig. 3 Beginning with the triangle shown in Fig. 3, prove that \(\sin 60 ^ { \circ } = \frac { \sqrt { 3 } } { 2 }\).
AnswerMarks Guidance
triangle divided into 2 rt angled tris \(\sqrt{3}\) and 1 indicated; 60 indicatedH1, S1, A1 3 marks total 
triangle divided into 2 rt angled tris $\sqrt{3}$ and 1 indicated; 60 indicated | H1, S1, A1 | 3 marks total
3

Fig. 3

Beginning with the triangle shown in Fig. 3, prove that $\sin 60 ^ { \circ } = \frac { \sqrt { 3 } } { 2 }$.

\hfill \mbox{\textit{OCR MEI C2 2006 Q3 [3]}}
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