For the curve \(C\) with equation \(y = x^4 - 8x^2 + 3\),
- find \(\frac{dy}{dx}\), [2]
- find the coordinates of each of the stationary points, [5]
- determine the nature of each stationary point. [3]
The point \(A\), on the curve \(C\), has \(x\)-coordinate \(1\).
- Find an equation for the normal to \(C\) at \(A\), giving your answer in the form \(ax + by + c = 0\), where \(a\), \(b\) and \(c\) are integers. [5]