Pre-U Pre-U 9794/1 2011 June — Question 7 7 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
Year2011
SessionJune
Marks7
TopicVectors 3D & Lines
TypeAngle between two vectors/lines (direct)
DifficultyStandard +0.3 This is a straightforward vector geometry question requiring substitution to find parameters (part i) and then applying the standard dot product formula for angle between lines (part ii). Both parts use routine A-level techniques with no novel insight required, making it slightly easier than average.
Spec4.04a Line equations: 2D and 3D, cartesian and vector forms4.04c Scalar product: calculate and use for angles

  1. Given that the point \((-1, -2, 4)\) lies on both the lines $$\mathbf{r} = \begin{pmatrix} 2 \\ -3 \\ a \end{pmatrix} + \lambda \begin{pmatrix} -3 \\ 2 \\ 1 \end{pmatrix} \quad \text{and} \quad \mathbf{r} = \begin{pmatrix} 2 \\ 4 \\ b \end{pmatrix} + \mu \begin{pmatrix} -1 \\ -2 \\ 1 \end{pmatrix},$$ find \(a\) and \(b\). [3]
  2. Find the acute angle between the lines. [4]

AnswerMarks Guidance
(i) \(2 - 3\lambda = 2 - \mu\)B1 Obtain correct eqns
\(-3 + \lambda = 4 - 2\mu\)
Obtain \(\lambda = 1\) \(\mu = 3\)B1
Obtain \(a = 3\) and \(b = 1\)B1
(ii) \(\begin{pmatrix} -1 \\ -2 \\ 1 \end{pmatrix}\) and \(\begin{pmatrix} -3 \\ 1 \\ 1 \end{pmatrix}\)M1 Use correct vectors aef
\(\frac{(-3)(-1) + 1(-2) + 1(1)}{(\sqrt{11})(\sqrt{6})}\)M1 Use correct dot product formula
\(= \frac{2}{\sqrt{66}}\) (= 0.246)B1 Find the length of any vector
Obtain \(75.7°\)A1 [7]
(i) $2 - 3\lambda = 2 - \mu$ | B1 | Obtain correct eqns

$-3 + \lambda = 4 - 2\mu$ |

Obtain $\lambda = 1$ $\mu = 3$ | B1 |

Obtain $a = 3$ and $b = 1$ | B1 |

(ii) $\begin{pmatrix} -1 \\ -2 \\ 1 \end{pmatrix}$ and $\begin{pmatrix} -3 \\ 1 \\ 1 \end{pmatrix}$ | M1 | Use correct vectors aef

$\frac{(-3)(-1) + 1(-2) + 1(1)}{(\sqrt{11})(\sqrt{6})}$ | M1 | Use correct dot product formula

$= \frac{2}{\sqrt{66}}$ (= 0.246) | B1 | Find the length of any vector

Obtain $75.7°$ | A1 | [7] | Obtain acute answer only cao
\begin{enumerate}[label=(\roman*)]
\item Given that the point $(-1, -2, 4)$ lies on both the lines
$$\mathbf{r} = \begin{pmatrix} 2 \\ -3 \\ a \end{pmatrix} + \lambda \begin{pmatrix} -3 \\ 2 \\ 1 \end{pmatrix} \quad \text{and} \quad \mathbf{r} = \begin{pmatrix} 2 \\ 4 \\ b \end{pmatrix} + \mu \begin{pmatrix} -1 \\ -2 \\ 1 \end{pmatrix},$$
find $a$ and $b$. [3]
\item Find the acute angle between the lines. [4]
\end{enumerate}

\hfill \mbox{\textit{Pre-U Pre-U 9794/1 2011 Q7 [7]}}