Pre-U Pre-U 9794/1 2011 June — Question 1 3 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
Year2011
SessionJune
Marks3
TopicStraight Lines & Coordinate Geometry
TypeEquation of line through two points
DifficultyEasy -1.8 This is a straightforward coordinate geometry question requiring only the standard two-step process: calculate gradient from two points, then substitute to find the y-intercept. It's a routine textbook exercise with no problem-solving element, significantly easier than average A-level questions.
Spec1.03a Straight lines: equation forms y=mx+c, ax+by+c=0
Find the equation of the line passing through the points \((-2, 5)\) and \((4, -7)\). Give your answer in the form \(y = mx + c\). [3]
AnswerMarks Guidance
(i) Gradient = \(-2\)B1 Accept aef or method e.g sim eqns \(5 = -2m + c\) and \(-7 = 4m + c\) and substitution for \(c\)
Attempt eqn of line \(y = -2x + 1\)M1, A1 Accept any simplified form
[3] 
(i) Gradient = $-2$ | B1 | Accept aef or method e.g sim eqns $5 = -2m + c$ and $-7 = 4m + c$ and substitution for $c$

Attempt eqn of line $y = -2x + 1$ | M1, A1 | Accept any simplified form

| [3] |
Find the equation of the line passing through the points $(-2, 5)$ and $(4, -7)$. Give your answer in the form $y = mx + c$. [3]

\hfill \mbox{\textit{Pre-U Pre-U 9794/1 2011 Q1 [3]}}
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