Pre-U Pre-U 9794/1 2011 June — Question 6 7 marks

Exam BoardPre-U
ModulePre-U 9794/1 (Pre-U Mathematics Paper 1)
Year2011
SessionJune
Marks7
TopicNewton-Raphson method
TypeNewton-Raphson with trigonometric or exponential functions
DifficultyStandard +0.3 This question combines routine sketching of standard functions with a straightforward application of the Newton-Raphson method. Part (i) requires recognizing that exponential and linear graphs intersect once (standard curve sketching), while part (ii) is a direct algorithmic application of Newton-Raphson with a given starting value—no conceptual difficulty or problem-solving insight required beyond following the standard procedure.
Spec1.06a Exponential function: a^x and e^x graphs and properties1.09d Newton-Raphson method

  1. Sketch, on a single diagram, the graphs of \(y = e^{3x}\) and \(y = x\) and state the number of roots of the equation \(e^{3x} = x\). [3]
  2. Use the Newton-Raphson method with \(x_0 = 0\) to determine the value of a root of the equation \(e^{3x} = x\) correct to 3 decimal places. [4]

AnswerMarks Guidance
(i) A positive exponential graphB1
Straight line with positive slopeB1
Show or state two intersections or rootsB1*
(ii) \(x_{n+1} = x_n - \frac{e^{0.2x} - x}{0.2e^{0.2x} - 1}\)M1, B1 Use correct NR formula. Correct derivative
M1*Starts at 0 and states at least two iterates. States 1.296
\(0, 1.25, 1.2958, 1.2959\)A1 [7]
(i) A positive exponential graph | B1 |

Straight line with positive slope | B1 |

Show or state two intersections or roots | B1* |

(ii) $x_{n+1} = x_n - \frac{e^{0.2x} - x}{0.2e^{0.2x} - 1}$ | M1, B1 | Use correct NR formula. Correct derivative

| M1* | Starts at 0 and states at least two iterates. States 1.296

$0, 1.25, 1.2958, 1.2959$ | A1 | [7] |
\begin{enumerate}[label=(\roman*)]
\item Sketch, on a single diagram, the graphs of $y = e^{3x}$ and $y = x$ and state the number of roots of the equation $e^{3x} = x$. [3]
\item Use the Newton-Raphson method with $x_0 = 0$ to determine the value of a root of the equation $e^{3x} = x$ correct to 3 decimal places. [4]
\end{enumerate}

\hfill \mbox{\textit{Pre-U Pre-U 9794/1 2011 Q6 [7]}}