SPS SPS FM 2019 — Question 9 9 marks

Exam BoardSPS
ModuleSPS FM (SPS FM)
Year2019
Marks9
TopicProof by induction
TypeProve recurrence relation formula
DifficultyStandard +0.3 This is a standard two-part induction question. Part (a) involves proving a recurrence relation formula by induction with straightforward algebra. Part (b) requires induction on a summation formula, which is slightly more involved algebraically but follows a completely standard template. Both parts are routine exercises in mathematical induction with no novel problem-solving required, making this slightly easier than average for A-level Further Maths.
Spec4.01a Mathematical induction: construct proofs

  1. Given that \(u_{n+1} = 5u_n + 4\), \(u_1 = 4\), prove by induction that \(u_n = 5^n - 1\). [4]
  2. For all positive integers, \(n \geq 2\), prove by induction that $$\sum_{r=2}^{n} r^2(r-1) = \frac{1}{12}n(n-1)(n+1)(3n+2)$$ [5]

\begin{enumerate}[label=(\alph*)]
\item Given that $u_{n+1} = 5u_n + 4$, $u_1 = 4$, prove by induction that $u_n = 5^n - 1$. [4]
\item For all positive integers, $n \geq 2$, prove by induction that
$$\sum_{r=2}^{n} r^2(r-1) = \frac{1}{12}n(n-1)(n+1)(3n+2)$$
[5]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS FM 2019 Q9 [9]}}