SPS SPS FM 2019 — Question 11 10 marks

Exam BoardSPS
ModuleSPS FM (SPS FM)
Year2019
Marks10
TopicBinomial Theorem (positive integer n)
TypeCoefficients in arithmetic/geometric progression
DifficultyChallenging +1.2 This is a multi-part binomial expansion problem requiring algebraic manipulation to establish a relationship between coefficients forming a GP, then applying this in specific cases. Part (a) involves setting up equations from the GP condition and algebraic simplification (standard but multi-step). Parts (b) and (c) are computational applications. The question requires careful algebra and understanding of GP properties, but follows a clear path without requiring novel insight—moderately above average difficulty for Further Maths.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

In the question you must show detailed reasoning Given that the coefficients of \(x\), \(x^2\) and \(x^4\) in the expansion of \((1 + kx)^n\) are the consecutive terms of a geometric series, where \(n \geq 4\) and \(k\) is a positive constant
  1. Show that $$k = \frac{6(n-1)}{(n-2)(n-3)}$$ [4]
  2. For the case when \(k = \frac{7}{2}\), find the value of \(n\). [2]
  3. Given that \(k = \frac{7}{5}\), \(n\) is a positive integer, and that the first term of the geometric series is the coefficient of \(x\), find the number of terms required for the sum of the geometric series to exceed \(1.12 \times 10^{12}\). [4]

In the question you must show detailed reasoning

Given that the coefficients of $x$, $x^2$ and $x^4$ in the expansion of $(1 + kx)^n$ are the consecutive terms of a geometric series, where $n \geq 4$ and $k$ is a positive constant

\begin{enumerate}[label=(\alph*)]
\item Show that $$k = \frac{6(n-1)}{(n-2)(n-3)}$$ [4]
\item For the case when $k = \frac{7}{2}$, find the value of $n$. [2]
\item Given that $k = \frac{7}{5}$, $n$ is a positive integer, and that the first term of the geometric series is the coefficient of $x$, find the number of terms required for the sum of the geometric series to exceed $1.12 \times 10^{12}$. [4]
\end{enumerate}

\hfill \mbox{\textit{SPS SPS FM 2019 Q11 [10]}}