In the question you must show detailed reasoning
Given that \(\log_a x = \frac{\log_n x}{\log_n a}\), show that the sum of the infinite series, where \(n = 0,1,2...\),
$$\log_2 e - \log_4 e + \log_{16} e - \cdots + (-1)^n \log_{2^{2^n}} e + \cdots$$
is
$$\frac{1}{\ln(2\sqrt{2})}$$
[5]
[Total marks: 65]