AQA Paper 3 Specimen — Question 7 12 marks

Exam BoardAQA
ModulePaper 3 (Paper 3)
SessionSpecimen
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNumerical integration
TypeTrapezium rule with stated number of strips
DifficultyStandard +0.8 This is a multi-part question requiring second derivative analysis to find concavity (involving product/chain rule with exponentials), numerical integration via trapezium rule, understanding of why trapezium rule underestimates on concave functions, and a proof involving bounds. While each individual technique is A-level standard, the combination of calculus concepts, numerical methods, and proof reasoning with error bounds makes this moderately challenging—above average but not exceptionally difficult.
Spec1.07f Convexity/concavity: points of inflection1.07p Points of inflection: using second derivative1.09f Trapezium rule: numerical integration

The diagram shows part of the graph of \(y = e^{-x^2}\) \includegraphics{figure_7} The graph is formed from two convex sections, where the gradient is increasing, and one concave section, where the gradient is decreasing.
  1. Find the values of \(x\) for which the graph is concave. [4 marks]
  2. The finite region bounded by the \(x\)-axis and the lines \(x = 0.1\) and \(x = 0.5\) is shaded. \includegraphics{figure_7b} Use the trapezium rule, with 4 strips, to find an estimate for \(\int_{0.1}^{0.5} e^{-x^2} dx\) Give your estimate to four decimal places. [3 marks]
  3. Explain with reference to your answer in part (a), why the answer you found in part (b) is an underestimate. [2 marks]
  4. By considering the area of a rectangle, and using your answer to part (b), prove that the shaded area is 0.4 correct to 1 decimal place. [3 marks]

Question 7:

AnswerMarks Guidance
7(a)Finds 2nd derivative and sets up an
inequalityAO3.1a M1
=−2xe−x2
dx
d2y
=−2e−x2 +4x2e−x2
dx2
−2e−x2 +4x2e−x2 <0
4x2 −2<0
2 2
− < x<
2 2
AnswerMarks Guidance
Obtains correct first derivativeAO1.1b A1
Obtains second derivative correct
AnswerMarks Guidance
from ‘their’ first derivativeAO1.1b A1F
Deduces correct final inequality
AnswerMarks Guidance
(could use set notation)AO2.2a A1
(b)Uses trapezium rule AO1.1a
∫ e−x2 dx≈ (e−0.01+e−0.25
2
0.1
+2(e−0.04 +e−0.09 +e−0.16))
0.3611
AnswerMarks Guidance
Trapezium rule entries all correctAO1.1b A1
Finds correct valueAO1.1b A1
(c)References area being completely
within concave section
AnswerMarks Guidance
So…AO2.4 E1
2 2
[ 0 . 1 , 0 . 5 ]≈⊂ − , 
 2 2 
∴ area is completely within
concave section
Hence trapezia lie below curve
and give an under-estimate for
the area
Trapezia all fall completely
underneath the curve therefore
underestimate (only award this
mark if previous E1 has been
AnswerMarks Guidance
awarded)AO2.4 E1
(d)Uses suitable rectangle to obtain
over-estimateAO3.1a B1
hand edge the same height as
the curve will produce an over-
estimate
Area of rectangle =
0.4×e−0.12
= 0.396...
∴ 0.36< A<0.40
So A = 0.4 to 1 dp
Explains that this rectangle lies
AnswerMarks Guidance
above the curveAO2.4 E1
Constructs rigorous mathematical
argument about accuracy, which
leads to required result
Only award if they have a
completely correct solution, which
is clear, easy to follow and
AnswerMarks Guidance
contains no slips.AO2.1 R1
Total12
QMarking Instructions AO
Question 7:
--- 7(a) ---
7(a) | Finds 2nd derivative and sets up an
inequality | AO3.1a | M1 | dy
=−2xe−x2
dx
d2y
=−2e−x2 +4x2e−x2
dx2
−2e−x2 +4x2e−x2 <0
4x2 −2<0
2 2
− < x<
2 2
Obtains correct first derivative | AO1.1b | A1
Obtains second derivative correct
from ‘their’ first derivative | AO1.1b | A1F
Deduces correct final inequality
(could use set notation) | AO2.2a | A1
(b) | Uses trapezium rule | AO1.1a | M1 | 0.5 0.1
∫ e−x2 dx≈ (e−0.01+e−0.25
2
0.1
+2(e−0.04 +e−0.09 +e−0.16))
0.3611
Trapezium rule entries all correct | AO1.1b | A1
Finds correct value | AO1.1b | A1
(c) | References area being completely
within concave section
So… | AO2.4 | E1 |  
2 2
[ 0 . 1 , 0 . 5 ]≈⊂ − , 
 2 2 
∴ area is completely within
concave section
Hence trapezia lie below curve
and give an under-estimate for
the area
Trapezia all fall completely
underneath the curve therefore
underestimate (only award this
mark if previous E1 has been
awarded) | AO2.4 | E1
(d) | Uses suitable rectangle to obtain
over-estimate | AO3.1a | B1 | Using a rectangle with the left
hand edge the same height as
the curve will produce an over-
estimate
Area of rectangle =
0.4×e−0.12
= 0.396...
∴ 0.36< A<0.40
So A = 0.4 to 1 dp
Explains that this rectangle lies
above the curve | AO2.4 | E1
Constructs rigorous mathematical
argument about accuracy, which
leads to required result
Only award if they have a
completely correct solution, which
is clear, easy to follow and
contains no slips. | AO2.1 | R1
Total | 12
Q | Marking Instructions | AO | Marks | Typical Solution
The diagram shows part of the graph of $y = e^{-x^2}$

\includegraphics{figure_7}

The graph is formed from two convex sections, where the gradient is increasing, and one concave section, where the gradient is decreasing.

\begin{enumerate}[label=(\alph*)]
\item Find the values of $x$ for which the graph is concave. [4 marks]

\item The finite region bounded by the $x$-axis and the lines $x = 0.1$ and $x = 0.5$ is shaded.

\includegraphics{figure_7b}

Use the trapezium rule, with 4 strips, to find an estimate for $\int_{0.1}^{0.5} e^{-x^2} dx$

Give your estimate to four decimal places. [3 marks]

\item Explain with reference to your answer in part (a), why the answer you found in part (b) is an underestimate. [2 marks]

\item By considering the area of a rectangle, and using your answer to part (b), prove that the shaded area is 0.4 correct to 1 decimal place. [3 marks]
\end{enumerate}

\hfill \mbox{\textit{AQA Paper 3  Q7 [12]}}