AQA Paper 3 Specimen — Question 2 6 marks

Exam BoardAQA
ModulePaper 3 (Paper 3)
SessionSpecimen
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSine and Cosine Rules
TypeTriangle with circular sector
DifficultyModerate -0.3 This is a straightforward multi-part trigonometry question requiring basic right-angled triangle work (finding sin θ from given sides), calculator use for inverse trig, and standard sector area formula. All techniques are routine A-level applications with no problem-solving insight needed, making it slightly easier than average.
Spec1.05d Radians: arc length s=r*theta and sector area A=1/2 r^2 theta1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=1

A wooden frame is to be made to support some garden decking. The frame is to be in the shape of a sector of a circle. The sector \(OAB\) is shown in the diagram, with a wooden plank \(AC\) added to the frame for strength. \(OA\) makes an angle of \(\theta\) with \(OB\). \includegraphics{figure_2}
  1. Show that the exact value of \(\sin\theta\) is \(\frac{4\sqrt{14}}{15}\) [3 marks]
  2. Write down the value of \(\theta\) in radians to 3 significant figures. [1 mark]
  3. Find the area of the garden that will be covered by the decking. [2 marks]

Question 2:

AnswerMarks Guidance
2(a)Makes clear attempt to use the
cosine ruleAO3.1a M1
32 +52 −62 1
cosθ= =−
30 15
2
 1 
∴sinθ= 1− −
 
 15
4 14
sinθ= (AG)
15
AnswerMarks Guidance
Uses trig identity with ‘their’ cosAO1.1a M1
𝜃𝜃
Constructs rigorous argument
leading to correct result AG
Only award if they have a
completely correct solution, which
is clear, easy to follow and
AnswerMarks Guidance
contains no slipsAO2.1 R1
(b)Writes down correct angle AO2.2a
(c)1
Uses ‘their’ angle in r2θ
AnswerMarks Guidance
2AO1.1a M1
A= ×52×1.64
2
= 20.5 m2
Correct area
FT use of incorrect obtuse angle
provided both M1 marks awarded
AnswerMarks Guidance
in part (a) and M1 awarded in (c)AO1.1b A1F
Total6
QMarking Instructions AO
Question 2:
--- 2(a) ---
2(a) | Makes clear attempt to use the
cosine rule | AO3.1a | M1 | 62 = 32 + 52 − 2×3×5cosθ
32 +52 −62 1
cosθ= =−
30 15
2
 1 
∴sinθ= 1− −
 
 15
4 14
sinθ= (AG)
15
Uses trig identity with ‘their’ cos | AO1.1a | M1
𝜃𝜃
Constructs rigorous argument
leading to correct result AG
Only award if they have a
completely correct solution, which
is clear, easy to follow and
contains no slips | AO2.1 | R1
(b) | Writes down correct angle | AO2.2a | B1 | 1.64
(c) | 1
Uses ‘their’ angle in r2θ
2 | AO1.1a | M1 | 1
A= ×52×1.64
2
= 20.5 m2
Correct area
FT use of incorrect obtuse angle
provided both M1 marks awarded
in part (a) and M1 awarded in (c) | AO1.1b | A1F
Total | 6
Q | Marking Instructions | AO | Marks | Typical Solution
A wooden frame is to be made to support some garden decking. The frame is to be in the shape of a sector of a circle. The sector $OAB$ is shown in the diagram, with a wooden plank $AC$ added to the frame for strength. $OA$ makes an angle of $\theta$ with $OB$.

\includegraphics{figure_2}

\begin{enumerate}[label=(\alph*)]
\item Show that the exact value of $\sin\theta$ is $\frac{4\sqrt{14}}{15}$ [3 marks]

\item Write down the value of $\theta$ in radians to 3 significant figures. [1 mark]

\item Find the area of the garden that will be covered by the decking. [2 marks]
\end{enumerate}

\hfill \mbox{\textit{AQA Paper 3  Q2 [6]}}