AQA Paper 3 Specimen — Question 1 1 marks

Exam BoardAQA
ModulePaper 3 (Paper 3)
SessionSpecimen
Marks1
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAreas by integration
TypeArea under polynomial curve
DifficultyEasy -1.8 This is a 1-mark multiple choice question requiring recognition that the area under y = x² - 9 from x = -3 to x = 3 equals ∫(x² - 9)dx = [x³/3 - 9x] = 0 - (-18) = -18, or that by symmetry it's 2∫₀³(x² - 9)dx. It's purely routine integration with no problem-solving, made even easier by being multiple choice where students can eliminate obviously wrong answers.
Spec1.08e Area between curve and x-axis: using definite integrals

The graph of \(y = x^2 - 9\) is shown below. \includegraphics{figure_1} Find the area of the shaded region. Circle your answer. [1 mark] \(-18\) \quad\quad \(-6\) \quad\quad \(6\) \quad\quad \(18\)

Question 1:
AnswerMarks Guidance
1Circles correct answer AO1.1b
Total1
Question 1:
1 | Circles correct answer | AO1.1b | B1 | 18
Total | 1
The graph of $y = x^2 - 9$ is shown below.

\includegraphics{figure_1}

Find the area of the shaded region.
Circle your answer.
[1 mark]

$-18$ \quad\quad $-6$ \quad\quad $6$ \quad\quad $18$

\hfill \mbox{\textit{AQA Paper 3  Q1 [1]}}