AQA Paper 3 Specimen — Question 9 3 marks

Exam BoardAQA
ModulePaper 3 (Paper 3)
SessionSpecimen
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Distribution
TypeDirect binomial probability calculation
DifficultyModerate -0.8 Part (a) is a direct application of the binomial probability formula with given n=25, p=1680/2400=0.7, and x=22—purely computational with no conceptual challenge. Part (b) requires recognizing that households on the same street likely aren't independent (a basic understanding of binomial assumptions), but this is a standard textbook consideration. Overall, this is easier than average: straightforward calculation plus routine recall of distribution assumptions.
Spec2.04b Binomial distribution: as model B(n,p)2.04c Calculate binomial probabilities

A survey has found that, of the 2400 households in Growmore, 1680 eat home-grown fruit and vegetables.
  1. Using the binomial distribution, find the probability that, out of a random sample of 25 households in Growmore, exactly 22 eat home-grown fruit and vegetables. [2 marks]
  2. Give a reason why you would not expect your calculation in part (a) to be valid for the 25 households in Gifford Terrace, a residential road in Growmore. [1 mark]

Question 9:

AnswerMarks Guidance
9(a)Finds value for p AO1.1a
p= =0.7
2400
Finds correct probability
AnswerMarks Guidance
from calculatorAO1.1b A1
P(X = 22) = 0.0243
AnswerMarks
(b)Explains the reason why
the model may no longer
AnswerMarks Guidance
apply in contextAO3.5b E1
gardens) will be of similar types, and
hence similar owners, so not likely to
be independent as binomial model
requires.
AnswerMarks Guidance
Total3
QMarking Instructions AO
Question 9:
--- 9(a) ---
9(a) | Finds value for p | AO1.1a | M1 | 1680
p= =0.7
2400
Finds correct probability
from calculator | AO1.1b | A1 | Using X ~ B(25,0.7),
P(X = 22) = 0.0243
(b) | Explains the reason why
the model may no longer
apply in context | AO3.5b | E1 | It is likely that all the houses (and
gardens) will be of similar types, and
hence similar owners, so not likely to
be independent as binomial model
requires.
Total | 3
Q | Marking Instructions | AO | Marks | Typical Solution
A survey has found that, of the 2400 households in Growmore, 1680 eat home-grown fruit and vegetables.

\begin{enumerate}[label=(\alph*)]
\item Using the binomial distribution, find the probability that, out of a random sample of 25 households in Growmore, exactly 22 eat home-grown fruit and vegetables. [2 marks]

\item Give a reason why you would not expect your calculation in part (a) to be valid for the 25 households in Gifford Terrace, a residential road in Growmore. [1 mark]
\end{enumerate}

\hfill \mbox{\textit{AQA Paper 3  Q9 [3]}}