| Exam Board | AQA |
|---|---|
| Module | Paper 2 (Paper 2) |
| Session | Specimen |
| Marks | 4 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Travel graphs |
| Type | Find acceleration from SUVAT |
| Difficulty | Moderate -0.8 This is a straightforward derivation of standard SUVAT equations from first principles using basic algebra and gradient interpretation. Part (a) requires simple gradient calculation (1 mark), and part (b) is a guided algebraic manipulation with clear steps provided by the given displacement formula. This is easier than average as it's purely mechanical algebra with no problem-solving insight required. |
| Spec | 3.02b Kinematic graphs: displacement-time and velocity-time3.02c Interpret kinematic graphs: gradient and area3.02d Constant acceleration: SUVAT formulae |
| Answer | Marks | Guidance |
|---|---|---|
| 12(a) | States correct expression for a | AO1.1b |
| Answer | Marks | Guidance |
|---|---|---|
| (b) | Rearranges to make T the subject | |
| of the formula | AO2.1 | R1 |
| Answer | Marks | Guidance |
|---|---|---|
| attempts to eliminate T | AO2.1 | R1 |
| Answer | Marks | Guidance |
|---|---|---|
| contains no slips | AO2.1 | R1 |
| Total | 4 | |
| Q | Marking Instructions | AO |
Question 12:
--- 12(a) ---
12(a) | States correct expression for a | AO1.1b | B1 | V U
a
T
(b) | Rearranges to make T the subject
of the formula | AO2.1 | R1 | V U
T
a
1 V U
S (U V)
2 a
2as (U V)(V U)
V2 U2 2aS (AG)
Uses given expression for S and
attempts to eliminate T | AO2.1 | R1
Completes argument to reach
required result AG
Only award if they have a
completely correct solution, which
is clear, easy to follow and
contains no slips | AO2.1 | R1
Total | 4
Q | Marking Instructions | AO | Marks | Typical SolutionA particle moves on a straight line with a constant acceleration, $a$ m s$^{-2}$.
The initial velocity of the particle is $U$ m s$^{-1}$.
After $T$ seconds the particle has velocity $V$ m s$^{-1}$.
This information is shown on the velocity-time graph.
\includegraphics{figure_12}
The displacement, $S$ metres, of the particle from its initial position at time $T$ seconds is given by the formula
$$S = \frac{1}{2}(U + V)T$$
\begin{enumerate}[label=(\alph*)]
\item By considering the gradient of the graph, or otherwise, write down a formula for $a$ in terms of $U$, $V$ and $T$.
[1 mark]
\item Hence show that $V^2 = U^2 + 2aS$
[3 marks]
\end{enumerate}
\hfill \mbox{\textit{AQA Paper 2 Q12 [4]}}