AQA Paper 2 Specimen — Question 7 4 marks

Exam BoardAQA
ModulePaper 2 (Paper 2)
SessionSpecimen
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProof
TypeIdentifying errors in proofs
DifficultyStandard +0.3 Part (a) requires recognizing that checking examples isn't a proof (basic understanding of proof methodology). Part (b) requires representing consecutive odd numbers algebraically as (2n+1) and (2n+3), then showing their sum equals (2n+2)² - (2n)² using difference of squares—a standard algebraic proof with straightforward manipulation. This is easier than average A-level proof questions.
Spec1.01a Proof: structure of mathematical proof and logical steps1.01b Logical connectives: congruence, if-then, if and only if

A student notices that when he adds two consecutive odd numbers together the answer always seems to be the difference between two square numbers. He claims that this will always be true. He attempts to prove his claim as follows: Step 1: Check first few cases \(3 + 5 = 8\) and \(8 = 3^2 - 1^2\) \(5 + 7 = 12\) and \(12 = 4^2 - 2^2\) \(7 + 9 = 16\) and \(16 = 5^2 - 3^2\) Step 2: Use pattern to predict and check a large example \(101 + 103 = 204\) subtract 1 and divide by 2 for the first number Add 1 and divide by two for the second number \(52^2 - 50^2 = 204\) it works! Step 3: Conclusion The first few cases work and there is a pattern, which can be used to predict larger numbers. Therefore, it must be true for all consecutive odd numbers.
  1. Explain what is wrong with the student's "proof". [1 mark]
  2. Prove that the student's claim is correct. [3 marks]

Question 7:

AnswerMarks Guidance
7(a)States any correct reason AO2.3
proves it for those cases
AnswerMarks
(b)Commences an argument, writing
the sum of two consecutive odd
numbers algebraically
AnswerMarks Guidance
(at least two lines of argument)AO2.1 R1
can be written as
2n1 and 2n3
Their sum is
2n12n34n4
n2and (n2)2 are two square
numbers
Their difference is
(n2)2 n2
n2 4n4n2
4n4
Therefore the sum of two
consecutive odd numbers can
always be written as the
difference of two square numbers
At some point in the argument
correctly writes the difference of
two appropriate square numbers
AnswerMarks Guidance
algebraicallyAO2.5 R1
Correctly deduces the result from
AnswerMarks Guidance
correct workingAO2.2a R1
Total4
QMarking Instructions AO
Question 7:
--- 7(a) ---
7(a) | States any correct reason | AO2.3 | B1 | Just checking a few cases only
proves it for those cases
(b) | Commences an argument, writing
the sum of two consecutive odd
numbers algebraically
(at least two lines of argument) | AO2.1 | R1 | Two consecutive odd numbers
can be written as
2n1 and 2n3
Their sum is
2n12n34n4
n2and (n2)2 are two square
numbers
Their difference is
(n2)2 n2
n2 4n4n2
4n4
Therefore the sum of two
consecutive odd numbers can
always be written as the
difference of two square numbers
At some point in the argument
correctly writes the difference of
two appropriate square numbers
algebraically | AO2.5 | R1
Correctly deduces the result from
correct working | AO2.2a | R1
Total | 4
Q | Marking Instructions | AO | Marks | Typical Solution
A student notices that when he adds two consecutive odd numbers together the answer always seems to be the difference between two square numbers.

He claims that this will always be true.

He attempts to prove his claim as follows:

Step 1: Check first few cases

$3 + 5 = 8$ and $8 = 3^2 - 1^2$

$5 + 7 = 12$ and $12 = 4^2 - 2^2$

$7 + 9 = 16$ and $16 = 5^2 - 3^2$

Step 2: Use pattern to predict and check a large example

$101 + 103 = 204$

subtract 1 and divide by 2 for the first number

Add 1 and divide by two for the second number

$52^2 - 50^2 = 204$ it works!

Step 3: Conclusion

The first few cases work and there is a pattern, which can be used to predict larger numbers.

Therefore, it must be true for all consecutive odd numbers.

\begin{enumerate}[label=(\alph*)]
\item Explain what is wrong with the student's "proof".
[1 mark]

\item Prove that the student's claim is correct.
[3 marks]
\end{enumerate}

\hfill \mbox{\textit{AQA Paper 2  Q7 [4]}}