Easy -1.2 This is a straightforward moments equilibrium problem requiring only one equation: taking moments about C gives M(0.8) = 24(1.5-0.8). The setup is simple with clear given values, requiring basic recall of the moments principle with no problem-solving insight or multi-step reasoning beyond simple algebra.
A uniform rod, \(AB\), has length 3 metres and mass 24 kg.
A particle of mass \(M\) kg is attached to the rod at \(A\).
The rod is balanced in equilibrium on a support at \(C\), which is 0.8 metres from \(A\).
\includegraphics{figure_11}
Find the value of \(M\).
[2 marks]
Question 11:
11 | Uses correct forces to form a
moment equation (PI) | AO1.1a | M1 | Take moments about C :
Mg × 0.8 = 0.7 × 24
M = 21
Obtains correct value | AO1.1b | A1
Total | 2
A uniform rod, $AB$, has length 3 metres and mass 24 kg.
A particle of mass $M$ kg is attached to the rod at $A$.
The rod is balanced in equilibrium on a support at $C$, which is 0.8 metres from $A$.
\includegraphics{figure_11}
Find the value of $M$.
[2 marks]
\hfill \mbox{\textit{AQA Paper 2 Q11 [2]}}