A particle moves on a straight line with a constant acceleration, \(a\) m s\(^{-2}\).
The initial velocity of the particle is \(U\) m s\(^{-1}\).
After \(T\) seconds the particle has velocity \(V\) m s\(^{-1}\).
This information is shown on the velocity-time graph.
\includegraphics{figure_12}
The displacement, \(S\) metres, of the particle from its initial position at time \(T\) seconds is given by the formula
$$S = \frac{1}{2}(U + V)T$$
- By considering the gradient of the graph, or otherwise, write down a formula for \(a\) in terms of \(U\), \(V\) and \(T\).
[1 mark]
- Hence show that \(V^2 = U^2 + 2aS\)
[3 marks]