AQA Paper 2 2020 June — Question 13 3 marks

Exam BoardAQA
ModulePaper 2 (Paper 2)
Year2020
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypeUniform beam on two supports
DifficultyModerate -0.8 This is a straightforward moments equilibrium problem requiring only one equation (taking moments about C) and basic knowledge that a uniform rod's weight acts at its center. The calculation is simple arithmetic with no conceptual challengesโ€”significantly easier than average A-level questions which typically require multiple techniques or problem-solving insight.
Spec3.04a Calculate moments: about a point3.04b Equilibrium: zero resultant moment and force

A uniform rod, \(AB\), has length \(7\) metres and mass \(4\) kilograms. The rod rests on a single fixed pivot point, \(C\), where \(AC = 2\) metres. A particle of weight \(W\) newtons is fixed at \(A\), as shown in the diagram. \includegraphics{figure_13} The system is in equilibrium with the rod resting horizontally.
  1. Find \(W\), giving your answer in terms of \(g\). [2 marks]
  2. Explain how you have used the fact that the rod is uniform in part (a). [1 mark]

Question 13:

AnswerMarks
13(a)Finds a moment of a force about
any point.
Must have the form force x
distance.
Can be awarded for example for
2w, 7w, 5R, 2R
Condone use of 9.8, 9.81, 10
AnswerMarks Guidance
instead of g3.4 M1
๐‘Š๐‘Š = 3๐˜จ๐˜จ
Obtains w
AnswerMarks Guidance
CAO1.1b A1
= 3๐˜จ๐˜จ Subtotal2

AnswerMarks
13(b)Explains that the weight of the rod
acts through the midpoint or the
centre of mass is at the midpoint
AnswerMarks Guidance
(of the rod) OE3.5a E1
acts at the centre
AnswerMarks Guidance
Subtotal1
Question Total3
QMarking Instructions AO
Question 13:
--- 13(a) ---
13(a) | Finds a moment of a force about
any point.
Must have the form force x
distance.
Can be awarded for example for
2w, 7w, 5R, 2R
Condone use of 9.8, 9.81, 10
instead of g | 3.4 | M1 | 2๐‘Š๐‘Š = 1.5ร— 4๐˜จ๐˜จ
๐‘Š๐‘Š = 3๐˜จ๐˜จ
Obtains w
CAO | 1.1b | A1
= 3๐˜จ๐˜จ Subtotal | 2
--- 13(b) ---
13(b) | Explains that the weight of the rod
acts through the midpoint or the
centre of mass is at the midpoint
(of the rod) OE | 3.5a | E1 | The rod is uniform so its weight
acts at the centre
Subtotal | 1
Question Total | 3
Q | Marking Instructions | AO | Marks | Typical Solution
A uniform rod, $AB$, has length $7$ metres and mass $4$ kilograms.

The rod rests on a single fixed pivot point, $C$, where $AC = 2$ metres.

A particle of weight $W$ newtons is fixed at $A$, as shown in the diagram.

\includegraphics{figure_13}

The system is in equilibrium with the rod resting horizontally.

\begin{enumerate}[label=(\alph*)]
\item Find $W$, giving your answer in terms of $g$.
[2 marks]

\item Explain how you have used the fact that the rod is uniform in part (a).
[1 mark]
\end{enumerate}

\hfill \mbox{\textit{AQA Paper 2 2020 Q13 [3]}}