Easy -1.8 This is a trivial vector subtraction problem requiring only one step: subtract the given force from the resultant. It's a 1-mark multiple-choice question with no problem-solving required, just direct application of the formula 'other forces = resultant - known force'. Significantly easier than average A-level questions.
A number of forces act on a particle such that the resultant force is \(\begin{pmatrix} 6 \\ -3 \end{pmatrix}\) N
One of the forces acting on the particle is \(\begin{pmatrix} 8 \\ -5 \end{pmatrix}\) N
Calculate the total of the other forces acting on the particle.
Circle your answer.
\(\begin{pmatrix} 2 \\ -2 \end{pmatrix}\) N \quad \(\begin{pmatrix} 14 \\ -8 \end{pmatrix}\) N \quad \(\begin{pmatrix} -2 \\ 2 \end{pmatrix}\) N \quad \(\begin{pmatrix} -14 \\ 8 \end{pmatrix}\) N
[1 mark]
A number of forces act on a particle such that the resultant force is $\begin{pmatrix} 6 \\ -3 \end{pmatrix}$ N
One of the forces acting on the particle is $\begin{pmatrix} 8 \\ -5 \end{pmatrix}$ N
Calculate the total of the other forces acting on the particle.
Circle your answer.
$\begin{pmatrix} 2 \\ -2 \end{pmatrix}$ N \quad $\begin{pmatrix} 14 \\ -8 \end{pmatrix}$ N \quad $\begin{pmatrix} -2 \\ 2 \end{pmatrix}$ N \quad $\begin{pmatrix} -14 \\ 8 \end{pmatrix}$ N
[1 mark]
\hfill \mbox{\textit{AQA Paper 2 2020 Q11 [1]}}