AQA Paper 2 2020 June — Question 3 3 marks

Exam BoardAQA
ModulePaper 2 (Paper 2)
Year2020
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeBinomial with negative or fractional powers of x
DifficultyModerate -0.3 This is a straightforward application of the binomial theorem requiring identification of the correct term where powers of x sum to x^2, then calculation using binomial coefficients. It's slightly easier than average as it's a standard 3-mark technique question with no conceptual difficulty, though students must be careful with the algebra and negative powers.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

Find the coefficient of \(x^2\) in the binomial expansion of \(\left(2x - \frac{3}{x}\right)^8\) [3 marks]

Question 3:
AnswerMarks
3(2x)5
Uses the product of and
3
 3
 ±  terms condone sign error
 x
and/or omission of nC term
r
Or
Obtains any two correct terms
AnswerMarks Guidance
(unsimplified) term3.1a M1
 3
8C ( 2x )5×  −  =56×32×−27x2
3  x
∴ coefficient is −48384
3
 3
Multiplies their (2x)5 and −  by
 x
8C or 8C or 56 OE
3 5
condone(2x)3
For this mark and
5
 3
 
AnswerMarks Guidance
 x1.1a M1
Obtains correct coefficient of x2
−48384
AnswerMarks Guidance
condone inclusion x21.1b A1
Total3
QMarking instructions AO
Question 3:
3 | (2x)5
Uses the product of and
3
 3
 ±  terms condone sign error
 x
and/or omission of nC term
r
Or
Obtains any two correct terms
(unsimplified) term | 3.1a | M1 | 3
 3
8C ( 2x )5×  −  =56×32×−27x2
3  x
∴ coefficient is −48384
3
 3
Multiplies their (2x)5 and −  by
 x
8C or 8C or 56 OE
3 5
condone(2x)3
For this mark and
5
 3
−
 
 x | 1.1a | M1
Obtains correct coefficient of x2
−48384
condone inclusion x2 | 1.1b | A1
Total | 3
Q | Marking instructions | AO | Marks | Typical solution
Find the coefficient of $x^2$ in the binomial expansion of $\left(2x - \frac{3}{x}\right)^8$

[3 marks]

\hfill \mbox{\textit{AQA Paper 2 2020 Q3 [3]}}