Easy -1.8 This is a straightforward 1-mark question testing basic understanding that parallel vectors are scalar multiples of each other. Students simply need to recognize that 8/-12 = a/9 and solve for a = -6, requiring only one calculation step with no problem-solving insight needed.
A particle, \(P\), is moving with constant velocity \(8\mathbf{i} - 12\mathbf{j}\)
A second particle, \(Q\), is moving with constant velocity \(a\mathbf{i} + 9\mathbf{j}\)
\(Q\) travels in a direction which is parallel to the motion of \(P\).
Find \(a\).
Circle your answer.
\(-6\) \quad \(-5\) \quad \(5\) \quad \(6\)
[1 mark]
A particle, $P$, is moving with constant velocity $8\mathbf{i} - 12\mathbf{j}$
A second particle, $Q$, is moving with constant velocity $a\mathbf{i} + 9\mathbf{j}$
$Q$ travels in a direction which is parallel to the motion of $P$.
Find $a$.
Circle your answer.
$-6$ \quad $-5$ \quad $5$ \quad $6$
[1 mark]
\hfill \mbox{\textit{AQA Paper 2 2020 Q12 [1]}}