Edexcel FP2 — Question 24 6 marks

Exam BoardEdexcel
ModuleFP2 (Further Pure Mathematics 2)
Marks6
PaperDownload PDF ↗
TopicSequences and series, recurrence and convergence
TypeProving standard summation formulae
DifficultyChallenging +1.2 This is a standard Further Maths proof technique requiring students to find an appropriate expression f(r) whose differences telescope to r². While it requires more sophistication than basic C1/C2 work (finding that f(r) = r(r+1)(2r+1)/6 works), it's a well-practiced method in FP2 with a clear algorithmic approach. The 6 marks reflect multiple steps but no novel insight is needed.
Spec4.06b Method of differences: telescoping series

Prove by the method of differences that \(\sum_{r=1}^{n} r^2 = \frac{1}{6}n(n + 1)(2n + 1)\), \(n > 1\). [6]

Prove by the method of differences that $\sum_{r=1}^{n} r^2 = \frac{1}{6}n(n + 1)(2n + 1)$, $n > 1$.
[6]

\hfill \mbox{\textit{Edexcel FP2  Q24 [6]}}