Edexcel FP2 — Question 36 5 marks

Exam BoardEdexcel
ModuleFP2 (Further Pure Mathematics 2)
Marks5
PaperDownload PDF ↗
TopicModulus function
TypeSketch y=|linear| and y=linear with unknown constants, then solve
DifficultyModerate -0.3 Part (a) is a straightforward sketch of a translated modulus function requiring basic knowledge of transformations. Part (b) involves solving a modulus inequality by considering cases (x ≥ 2a and x < 2a), which is a standard technique taught in FP2, though it requires careful algebraic manipulation and interpretation of the solution regions. This is slightly easier than average as it follows a well-practiced method without requiring novel insight.
Spec1.02g Inequalities: linear and quadratic in single variable1.02l Modulus function: notation, relations, equations and inequalities

  1. Sketch the graph of \(y = |x - 2a|\), given that \(a > 0\). [2]
  2. Solve \(|x - 2a| > 2x + a\), where \(a > 0\). [3]

\begin{enumerate}[label=(\alph*)]
\item Sketch the graph of $y = |x - 2a|$, given that $a > 0$. [2]

\item Solve $|x - 2a| > 2x + a$, where $a > 0$. [3]
\end{enumerate}

\hfill \mbox{\textit{Edexcel FP2  Q36 [5]}}