Edexcel C1 — Question 9 12 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Marks12
PaperDownload PDF ↗
TopicTangents, normals and gradients
TypeTangent parallel to given line
DifficultyModerate -0.8 This is a straightforward C1 question testing basic differentiation, finding x-intercepts by factoring, and using the gradient condition for parallel lines. All parts use standard techniques with clear signposting, requiring minimal problem-solving insight. Part (d) involves solving a quadratic equation but the setup is routine.
Spec1.07i Differentiate x^n: for rational n and sums1.07m Tangents and normals: gradient and equations

\includegraphics{figure_2} Figure 2 shows part of the curve \(C\) with equation $$y = (x - 1)(x^2 - 4).$$ The curve cuts the \(x\)-axis at the points \(P\), \((1, 0)\) and \(Q\), as shown in Figure 2.
  1. Write down the \(x\)-coordinate of \(P\) and the \(x\)-coordinate of \(Q\). [2]
  2. Show that \(\frac{dy}{dx} = 3x^2 - 2x - 4\). [3]
  3. Show that \(y = x + 7\) is an equation of the tangent to \(C\) at the point \((-1, 6)\). [2]
The tangent to \(C\) at the point \(R\) is parallel to the tangent at the point \((-1, 6)\).
  1. Find the exact coordinates of \(R\). [5]

\includegraphics{figure_2}

Figure 2 shows part of the curve $C$ with equation
$$y = (x - 1)(x^2 - 4).$$

The curve cuts the $x$-axis at the points $P$, $(1, 0)$ and $Q$, as shown in Figure 2.

\begin{enumerate}[label=(\alph*)]
\item Write down the $x$-coordinate of $P$ and the $x$-coordinate of $Q$. [2]
\item Show that $\frac{dy}{dx} = 3x^2 - 2x - 4$. [3]
\item Show that $y = x + 7$ is an equation of the tangent to $C$ at the point $(-1, 6)$. [2]
\end{enumerate}

The tangent to $C$ at the point $R$ is parallel to the tangent at the point $(-1, 6)$.

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{3}
\item Find the exact coordinates of $R$. [5]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1  Q9 [12]}}