Edexcel C1 — Question 7 8 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Marks8
PaperDownload PDF ↗
TopicIndefinite & Definite Integrals
TypeFind curve from gradient
DifficultyModerate -0.8 This is a straightforward C1 integration question requiring algebraic manipulation (expanding and simplifying with fractional powers) followed by routine integration using the power rule and finding a constant using boundary conditions. All steps are standard textbook procedures with no problem-solving insight required, making it easier than average but not trivial due to the multi-step nature.
Spec1.02a Indices: laws of indices for rational exponents1.08b Integrate x^n: where n != -1 and sums1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)

  1. Show that \(\frac{(3 - \sqrt{x})^2}{\sqrt{x}}\) can be written as \(9x^{-\frac{1}{2}} - 6 + x^{\frac{1}{2}}\). [2]
Given that \(\frac{dy}{dx} = \frac{(3 - \sqrt{x})^2}{\sqrt{x}}\), \(x > 0\), and that \(y = \frac{2}{3}\) at \(x = 1\),
  1. find \(y\) in terms of \(x\). [6]

\begin{enumerate}[label=(\alph*)]
\item Show that $\frac{(3 - \sqrt{x})^2}{\sqrt{x}}$ can be written as $9x^{-\frac{1}{2}} - 6 + x^{\frac{1}{2}}$. [2]
\end{enumerate}

Given that $\frac{dy}{dx} = \frac{(3 - \sqrt{x})^2}{\sqrt{x}}$, $x > 0$, and that $y = \frac{2}{3}$ at $x = 1$,

\begin{enumerate}[label=(\alph*)]
\setcounter{enumi}{1}
\item find $y$ in terms of $x$. [6]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1  Q7 [8]}}