Edexcel C1 — Question 7 9 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Marks9
PaperDownload PDF ↗
TopicStandard Integrals and Reverse Chain Rule
TypeFind curve equation from derivative (extended problem with normals, stationary points, or further geometry)
DifficultyModerate -0.3 This is a straightforward integration question requiring standard power rule application and using a point to find the constant of integration, followed by a routine tangent line calculation. While it involves multiple steps (9 marks total), each step uses basic C1 techniques with no problem-solving insight required, making it slightly easier than average.
Spec1.07i Differentiate x^n: for rational n and sums1.07l Derivative of ln(x): and related functions1.07m Tangents and normals: gradient and equations1.08a Fundamental theorem of calculus: integration as reverse of differentiation

The curve \(C\) has equation \(y = f(x)\), \(x \neq 0\), and the point \(P(2, 1)\) lies on \(C\). Given that $$f'(x) = 3x^2 - 6 - \frac{8}{x^3},$$
  1. find \(f(x)\). [5]
  2. Find an equation for the tangent to \(C\) at the point \(P\), giving your answer in the form \(y = mx + c\), where \(m\) and \(c\) are integers. [4]

The curve $C$ has equation $y = f(x)$, $x \neq 0$, and the point $P(2, 1)$ lies on $C$. Given that
$$f'(x) = 3x^2 - 6 - \frac{8}{x^3},$$

\begin{enumerate}[label=(\alph*)]
\item find $f(x)$. [5]
\item Find an equation for the tangent to $C$ at the point $P$, giving your answer in the form $y = mx + c$, where $m$ and $c$ are integers. [4]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1  Q7 [9]}}