Edexcel C1 — Question 3 5 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Marks5
PaperDownload PDF ↗
TopicStraight Lines & Coordinate Geometry
TypePerpendicular line through point
DifficultyEasy -1.3 This is a straightforward C1 coordinate geometry question requiring only basic substitution to verify a point lies on a line, then finding a perpendicular line using the negative reciprocal gradient rule. Both parts are routine textbook exercises with no problem-solving insight needed, making it easier than average.
Spec1.03a Straight lines: equation forms y=mx+c, ax+by+c=01.03b Straight lines: parallel and perpendicular relationships

The line \(L\) has equation \(y = 5 - 2x\).
  1. Show that the point \(P(3, -1)\) lies on \(L\). [1]
  2. Find an equation of the line perpendicular to \(L\), which passes through \(P\). Give your answer in the form \(ax + by + c = 0\), where \(a\), \(b\) and \(c\) are integers. [4]

The line $L$ has equation $y = 5 - 2x$.

\begin{enumerate}[label=(\alph*)]
\item Show that the point $P(3, -1)$ lies on $L$. [1]
\item Find an equation of the line perpendicular to $L$, which passes through $P$. Give your answer in the form $ax + by + c = 0$, where $a$, $b$ and $c$ are integers. [4]
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1  Q3 [5]}}