AQA Further AS Paper 2 Discrete 2020 June — Question 4 4 marks

Exam BoardAQA
ModuleFurther AS Paper 2 Discrete (Further AS Paper 2 Discrete)
Year2020
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicGraph Theory Fundamentals
TypeEuler's formula application
DifficultyChallenging +1.2 This question requires applying Euler's formula (V - E + F = 2) to a quadratic equation and using the Eulerian property (all vertices have even degree), but the algebraic manipulation is straightforward and the concepts are standard Further Maths content. The constraint that x must be even provides a simple check, making this a moderately above-average question that tests understanding rather than requiring novel insight.
Spec7.02l Planar graphs: planarity, subdivision, contraction7.02m Euler's formula: V + R = E + 2

4 The connected planar graph \(P\) is Eulerian and has at least one vertex of degree \(x\). Some of the properties of \(P\) are shown in the table below.
Number of
vertices
Number of
edges
Number of
faces
\(3 x + 6\)\(x ^ { 2 } + 8 x\)\(2 x ^ { 2 } + 2\)
Deduce the value of \(x\).
Fully justify your answer. \includegraphics[max width=\textwidth, alt={}, center]{21ed3b4e-a089-4607-b5d6-69d8aac03f31-07_2488_1716_219_153}

Question 4:
AnswerMarks Guidance
Answer/WorkingMark Guidance
As graph is planar and connected: \(v - e + f = 2\)M1 Uses Euler's formula for connected planar graphs
\(3x + 6 - (x^2 + 8x) + 2x^2 + 2 = 2\)M1 Forms a correct unsimplified equation in \(x\) using Euler's formula
\(x^2 - 5x + 6 = 0\), giving \(x = 3\) or \(x = 2\)A1 Solves quadratic and gives two solutions
An Eulerian graph cannot have a vertex of degree 3, therefore \(x = 2\)R1F Deduces \(x = 2\); only even values valid as \(P\) is Eulerian (FT their odd/even values of \(x\))
## Question 4:

| Answer/Working | Mark | Guidance |
|---|---|---|
| As graph is planar and connected: $v - e + f = 2$ | M1 | Uses Euler's formula for connected planar graphs |
| $3x + 6 - (x^2 + 8x) + 2x^2 + 2 = 2$ | M1 | Forms a correct unsimplified equation in $x$ using Euler's formula |
| $x^2 - 5x + 6 = 0$, giving $x = 3$ or $x = 2$ | A1 | Solves quadratic and gives two solutions |
| An Eulerian graph cannot have a vertex of degree 3, therefore $x = 2$ | R1F | Deduces $x = 2$; only even values valid as $P$ is Eulerian (FT their odd/even values of $x$) |

---
4 The connected planar graph $P$ is Eulerian and has at least one vertex of degree $x$.

Some of the properties of $P$ are shown in the table below.

\begin{center}
\begin{tabular}{ | c | c | c | }
\hline
\begin{tabular}{ c }
Number of \\
vertices \\
\end{tabular} & \begin{tabular}{ c }
Number of \\
edges \\
\end{tabular} & \begin{tabular}{ c }
Number of \\
faces \\
\end{tabular} \\
\hline
$3 x + 6$ & $x ^ { 2 } + 8 x$ & $2 x ^ { 2 } + 2$ \\
\hline
\end{tabular}
\end{center}

Deduce the value of $x$.\\
Fully justify your answer.\\

\includegraphics[max width=\textwidth, alt={}, center]{21ed3b4e-a089-4607-b5d6-69d8aac03f31-07_2488_1716_219_153}

\hfill \mbox{\textit{AQA Further AS Paper 2 Discrete 2020 Q4 [4]}}