AQA Further AS Paper 2 Discrete 2020 June — Question 5 6 marks

Exam BoardAQA
ModuleFurther AS Paper 2 Discrete (Further AS Paper 2 Discrete)
Year2020
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCritical Path Analysis
TypeCalculate early and late times
DifficultyModerate -0.3 This is a standard critical path analysis question requiring construction of an activity network, forward and backward passes to find early/late times, and analysis of a duration change. While it involves multiple activities and dependencies, the techniques are routine algorithmic procedures taught in Decision Maths with no novel problem-solving required. The multi-part structure and computational work place it slightly below average difficulty for A-level.
Spec7.05a Critical path analysis: activity on arc networks7.05b Forward and backward pass: earliest/latest times, critical activities

5 A restoration project is divided into a number of activities. The duration and predecessor(s) of each activity are shown in the table below.
ActivityImmediate predecessor(s)Duration (weeks)
\(A\)-10
B-5
CB12
D\(A\)8
\(E\)C, D4
\(F\)C, D3
\(G\)C, D7
\(H\)E, F8
\(I\)G6
\(J\)G15
KH, I5
\(L\)K4
5
  1. On the opposite page, construct an activity network for the project and fill in the earliest start time and latest finish time for each activity.
    [0pt] [4 marks] \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{21ed3b4e-a089-4607-b5d6-69d8aac03f31-09_533_289_2124_1548} \captionsetup{labelformat=empty} \caption{Turn over -}
    \end{figure} 5
  2. Due to a change of materials during the project, the duration of activity \(C\) is extended by 3 weeks. Determine the new minimum completion time of the project. \includegraphics[max width=\textwidth, alt={}, center]{21ed3b4e-a089-4607-b5d6-69d8aac03f31-11_2488_1716_219_153}

Question 5(a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Activity network with activities \(A\) to \(G\) drawn with correct arcsM1 Constructs activity network
All activities with correct arcs (condone extra 'End' activity with duration 0)A1 Completes activity network
Earliest start times: \(A\): \(0\), \(B\): \(0\), \(C\): \(5\), \(D\): \(10\), \(E\): \(18\), \(F\): \(18\), \(G\): \(18\), \(H\): \(22\), \(I\): \(25\), \(J\): \(25\), \(K\): \(31\), \(L\): \(36\)B1 Finds correctly the earliest start time for each activity
Latest finish times: \(A\): \(10\), \(B\): \(6\), \(C\): \(18\), \(D\): \(18\), \(E\): \(23\), \(F\): \(23\), \(G\): \(25\), \(H\): \(31\), \(I\): \(31\), \(J\): \(40\), \(K\): \(36\), \(L\): \(40\)B1F Finds correctly the latest finish times (FT their earliest start times)
Question 5(b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Activity \(C\) has a float of \(1\), so becomes critical as it is delayed by 3 weeksM1 Evaluates effect of increasing duration of \(C\) by 3 weeks (e.g. considers float of \(C\) or amends network)
The new minimum completion time is \(42\) weeksA1F Determines new minimum completion time as 42 weeks; condone '42' (FT their '40' from part (a))
## Question 5(a):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Activity network with activities $A$ to $G$ drawn with correct arcs | M1 | Constructs activity network |
| All activities with correct arcs (condone extra 'End' activity with duration 0) | A1 | Completes activity network |
| Earliest start times: $A$: $0$, $B$: $0$, $C$: $5$, $D$: $10$, $E$: $18$, $F$: $18$, $G$: $18$, $H$: $22$, $I$: $25$, $J$: $25$, $K$: $31$, $L$: $36$ | B1 | Finds correctly the earliest start time for each activity |
| Latest finish times: $A$: $10$, $B$: $6$, $C$: $18$, $D$: $18$, $E$: $23$, $F$: $23$, $G$: $25$, $H$: $31$, $I$: $31$, $J$: $40$, $K$: $36$, $L$: $40$ | B1F | Finds correctly the latest finish times (FT their earliest start times) |

## Question 5(b):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Activity $C$ has a float of $1$, so becomes critical as it is delayed by 3 weeks | M1 | Evaluates effect of increasing duration of $C$ by 3 weeks (e.g. considers float of $C$ or amends network) |
| The new minimum completion time is $42$ weeks | A1F | Determines new minimum completion time as 42 weeks; condone '42' (FT their '40' from part (a)) |

---
5 A restoration project is divided into a number of activities.

The duration and predecessor(s) of each activity are shown in the table below.

\begin{center}
\begin{tabular}{|l|l|l|}
\hline
Activity & Immediate predecessor(s) & Duration (weeks) \\
\hline
$A$ & - & 10 \\
\hline
B & - & 5 \\
\hline
C & B & 12 \\
\hline
D & $A$ & 8 \\
\hline
$E$ & C, D & 4 \\
\hline
$F$ & C, D & 3 \\
\hline
$G$ & C, D & 7 \\
\hline
$H$ & E, F & 8 \\
\hline
$I$ & G & 6 \\
\hline
$J$ & G & 15 \\
\hline
K & H, I & 5 \\
\hline
$L$ & K & 4 \\
\hline
\end{tabular}
\end{center}

5
\begin{enumerate}[label=(\alph*)]
\item On the opposite page, construct an activity network for the project and fill in the earliest start time and latest finish time for each activity.\\[0pt]
[4 marks]

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{21ed3b4e-a089-4607-b5d6-69d8aac03f31-09_533_289_2124_1548}
\captionsetup{labelformat=empty}
\caption{Turn over -}
\end{center}
\end{figure}

5
\item Due to a change of materials during the project, the duration of activity $C$ is extended by 3 weeks.

Determine the new minimum completion time of the project.\\

\includegraphics[max width=\textwidth, alt={}, center]{21ed3b4e-a089-4607-b5d6-69d8aac03f31-11_2488_1716_219_153}
\end{enumerate}

\hfill \mbox{\textit{AQA Further AS Paper 2 Discrete 2020 Q5 [6]}}