CAIE P3 2021 November — Question 3 6 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2021
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComplex Numbers Arithmetic
TypeComplex conjugate properties and proofs
DifficultyModerate -0.8 Part (a) is a straightforward proof requiring only the definition of complex conjugate applied to sums—pure algebraic manipulation with no insight needed. Part (b) is a routine linear equation in z once the conjugate property is applied. Both parts are below-average difficulty, being standard textbook exercises testing basic complex number definitions rather than problem-solving skills.
Spec4.02e Arithmetic of complex numbers: add, subtract, multiply, divide4.02i Quadratic equations: with complex roots4.02k Argand diagrams: geometric interpretation

3
  1. Given the complex numbers \(u = a + \mathrm { i } b\) and \(w = c + \mathrm { i } d\), where \(a , b , c\) and \(d\) are real, prove that \(( u + w ) ^ { * } = u ^ { * } + w ^ { * }\).
  2. Solve the equation \(( z + 2 + \mathrm { i } ) ^ { * } + ( 2 + \mathrm { i } ) z = 0\), giving your answer in the form \(x + \mathrm { i } y\) where \(x\) and \(y\) are real.

Question 3(a):
AnswerMarks Guidance
AnswerMark Guidance
Substitute for \(u\) and \(w\) and state correct conjugate of one sideB1
Express the other side without conjugates and confirm \((u+w)^* = u^* + w^*\)B1 Given answer. Needs explicit reference to conjugate of both sides
Total: 2 marks
Question 3(b):
AnswerMarks Guidance
AnswerMark Guidance
Substitute and remove conjugates to obtain a correct equation in \(x\) and \(y\)B1 e.g. \(x + 2 - (y+1)i + (2+i)(x+iy) = 0\)
Use \(i^2 = -1\) and equate real and imaginary parts to zeroM1
Obtain two correct equations in \(x\) and \(y\)A1 e.g. \(3x - y + 2 = 0\) and \(x + y - 1 = 0\). Allow \(xi + yi - i = 0\)
Solve and obtain answer \(z = -\frac{1}{4} + \frac{5}{4}i\)A1 Allow for real and imaginary parts stated separately
Total: 4 marks
## Question 3(a):

| Answer | Mark | Guidance |
|--------|------|----------|
| Substitute for $u$ and $w$ and state correct conjugate of one side | **B1** | |
| Express the other side without conjugates and confirm $(u+w)^* = u^* + w^*$ | **B1** | **Given answer.** Needs explicit reference to conjugate of both sides |

**Total: 2 marks**

## Question 3(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| Substitute and remove conjugates to obtain a correct equation in $x$ and $y$ | **B1** | e.g. $x + 2 - (y+1)i + (2+i)(x+iy) = 0$ |
| Use $i^2 = -1$ and equate real and imaginary parts to zero | **M1** | |
| Obtain two correct equations in $x$ and $y$ | **A1** | e.g. $3x - y + 2 = 0$ and $x + y - 1 = 0$. Allow $xi + yi - i = 0$ |
| Solve and obtain answer $z = -\frac{1}{4} + \frac{5}{4}i$ | **A1** | Allow for real and imaginary parts stated separately |

**Total: 4 marks**

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3
\begin{enumerate}[label=(\alph*)]
\item Given the complex numbers $u = a + \mathrm { i } b$ and $w = c + \mathrm { i } d$, where $a , b , c$ and $d$ are real, prove that $( u + w ) ^ { * } = u ^ { * } + w ^ { * }$.
\item Solve the equation $( z + 2 + \mathrm { i } ) ^ { * } + ( 2 + \mathrm { i } ) z = 0$, giving your answer in the form $x + \mathrm { i } y$ where $x$ and $y$ are real.
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2021 Q3 [6]}}