CAIE P3 2021 November — Question 11 11 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2021
SessionNovember
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicChain Rule
TypeShow that derivative equals expression
DifficultyStandard +0.3 Part (a) is a straightforward chain rule application with standard verification. Part (b) requires algebraic manipulation to derive a cubic equation from the derivative condition, which is routine. Part (c) is mechanical iteration requiring only calculator work. This is a standard multi-part question slightly easier than average due to the guided structure and lack of conceptual challenges.
Spec1.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^21.07r Chain rule: dy/dx = dy/du * du/dx and connected rates1.09d Newton-Raphson method

11 The equation of a curve is \(y = \sqrt { \tan x }\), for \(0 \leqslant x < \frac { 1 } { 2 } \pi\).
  1. Express \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) in terms of \(\tan x\), and verify that \(\frac { \mathrm { d } y } { \mathrm {~d} x } = 1\) when \(x = \frac { 1 } { 4 } \pi\).
    The value of \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) is also 1 at another point on the curve where \(x = a\), as shown in the diagram. \includegraphics[max width=\textwidth, alt={}, center]{87be326f-f638-43e9-a654-b7b53d5141ef-18_605_492_1493_822}
  2. Show that \(t ^ { 3 } + t ^ { 2 } + 3 t - 1 = 0\), where \(t = \tan a\).
  3. Use the iterative formula $$a _ { n + 1 } = \tan ^ { - 1 } \left( \frac { 1 } { 3 } \left( 1 - \tan ^ { 2 } a _ { n } - \tan ^ { 3 } a _ { n } \right) \right)$$ to determine \(a\) correct to 2 decimal places, giving the result of each iteration to 4 decimal places.
    If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.

Question 11(b):
AnswerMarks Guidance
AnswerMark Guidance
Equate answer to part (a) to 1 and obtain a quartic equation in \(t\) or \(\tan x\)\*M1 At least as far as \(\left(1+\tan^2 x\right)^2 = 4\tan x\)
Obtain correct answer, i.e. \(t^4 + 2t^2 - 4t + 1 = 0\)A1 Or equivalent horizontal form.
Commence division by \(t - 1\)DM1 As far as \(t^3 + t^2 + \ldots\) by long division or inspection. Allow verification by multiplying given answer by \(t - 1\).
Obtain the given answerA1
Total4
Question 11(c):
AnswerMarks Guidance
AnswerMark Guidance
Use the iterative process correctly with the given formula at least onceM1 Obtain one value and use that to obtain the next. Must be working in radians.
Obtain final answer \(a = 0.29\)A1
Show sufficient iterations to 4 d.p. to justify \(0.29\) to 2 d.p., or show there is a sign change in \((0.285, 0.295)\)A1 e.g. \(0.3, 0.2854, 0.2894, 0.2883, \ldots\) \(0.4, 0.2436, 0.2984, 0.2841, 0.2883, 0.2871, \ldots\) \(0.5, 0.1776, 0.3103, 0.2805, 0.2893, 0.2868, \ldots\)
Total3
## Question 11(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| Equate answer to part (a) to 1 and obtain a quartic equation in $t$ or $\tan x$ | \*M1 | At least as far as $\left(1+\tan^2 x\right)^2 = 4\tan x$ |
| Obtain correct answer, i.e. $t^4 + 2t^2 - 4t + 1 = 0$ | A1 | Or equivalent horizontal form. |
| Commence division by $t - 1$ | DM1 | As far as $t^3 + t^2 + \ldots$ by long division or inspection. Allow verification by multiplying given answer by $t - 1$. |
| Obtain the given answer | A1 | |
| **Total** | **4** | |

---

## Question 11(c):

| Answer | Mark | Guidance |
|--------|------|----------|
| Use the iterative process correctly with the given formula at least once | M1 | Obtain one value and use that to obtain the next. Must be working in radians. |
| Obtain final answer $a = 0.29$ | A1 | |
| Show sufficient iterations to 4 d.p. to justify $0.29$ to 2 d.p., or show there is a sign change in $(0.285, 0.295)$ | A1 | e.g. $0.3, 0.2854, 0.2894, 0.2883, \ldots$ $0.4, 0.2436, 0.2984, 0.2841, 0.2883, 0.2871, \ldots$ $0.5, 0.1776, 0.3103, 0.2805, 0.2893, 0.2868, \ldots$ |
| **Total** | **3** | |
11 The equation of a curve is $y = \sqrt { \tan x }$, for $0 \leqslant x < \frac { 1 } { 2 } \pi$.
\begin{enumerate}[label=(\alph*)]
\item Express $\frac { \mathrm { d } y } { \mathrm {~d} x }$ in terms of $\tan x$, and verify that $\frac { \mathrm { d } y } { \mathrm {~d} x } = 1$ when $x = \frac { 1 } { 4 } \pi$.\\

The value of $\frac { \mathrm { d } y } { \mathrm {~d} x }$ is also 1 at another point on the curve where $x = a$, as shown in the diagram.\\
\includegraphics[max width=\textwidth, alt={}, center]{87be326f-f638-43e9-a654-b7b53d5141ef-18_605_492_1493_822}
\item Show that $t ^ { 3 } + t ^ { 2 } + 3 t - 1 = 0$, where $t = \tan a$.
\item Use the iterative formula

$$a _ { n + 1 } = \tan ^ { - 1 } \left( \frac { 1 } { 3 } \left( 1 - \tan ^ { 2 } a _ { n } - \tan ^ { 3 } a _ { n } \right) \right)$$

to determine $a$ correct to 2 decimal places, giving the result of each iteration to 4 decimal places.\\

If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2021 Q11 [11]}}