CAIE P3 2021 November — Question 7 7 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2021
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFirst order differential equations (integrating factor)
TypeSeparable variables
DifficultyModerate -0.3 This is a straightforward separable variables question requiring standard technique: separate variables to get dy/y² = 4xe^(-2x)dx, integrate both sides (right side needs integration by parts), then apply initial condition. While integration by parts adds a step beyond the most basic separable equations, this remains a routine textbook exercise with no conceptual challenges or novel insights required.
Spec1.08k Separable differential equations: dy/dx = f(x)g(y)

7 The variables \(x\) and \(y\) satisfy the differential equation $$\mathrm { e } ^ { 2 x } \frac { \mathrm {~d} y } { \mathrm {~d} x } = 4 x y ^ { 2 }$$ and it is given that \(y = 1\) when \(x = 0\).
Solve the differential equation, obtaining an expression for \(y\) in terms of \(x\).

Question 7:
AnswerMarks Guidance
AnswerMarks Guidance
Separate variables correctlyB1 \(\int \frac{1}{y^2} dy = \int 4xe^{-2x} dx\)
\(\int \frac{1}{y^2} dy = -\frac{1}{y}\)B1 OE
Commence the other integration and reach \(axe^{-2x} + b\int e^{-2x} dx\)M1
Obtain \(-2xe^{-2x} + 2\int e^{-2x} dx\) or \(-\frac{1}{2}xe^{-2x} + \frac{1}{2}\int e^{-2x} dx\)A1 SOI (might have taken out factor of 4)
Complete integration and obtain \(-2xe^{-2x} - e^{-2x}\)A1
Evaluate a constant or use \(x=0\) and \(y=1\) as limits in a solution containing terms of the form \(\frac{p}{y}\), \(qxe^{-2x}\), \(re^{-2x}\), or equivalentM1
Obtain \(y = \frac{e^{2x}}{2x+1}\), or equivalent expression for \(y\)A1 ISW
## Question 7:

| Answer | Marks | Guidance |
|--------|-------|----------|
| Separate variables correctly | B1 | $\int \frac{1}{y^2} dy = \int 4xe^{-2x} dx$ |
| $\int \frac{1}{y^2} dy = -\frac{1}{y}$ | B1 | OE |
| Commence the other integration and reach $axe^{-2x} + b\int e^{-2x} dx$ | M1 | |
| Obtain $-2xe^{-2x} + 2\int e^{-2x} dx$ or $-\frac{1}{2}xe^{-2x} + \frac{1}{2}\int e^{-2x} dx$ | A1 | SOI (might have taken out factor of 4) |
| Complete integration and obtain $-2xe^{-2x} - e^{-2x}$ | A1 | |
| Evaluate a constant or use $x=0$ and $y=1$ as limits in a solution containing terms of the form $\frac{p}{y}$, $qxe^{-2x}$, $re^{-2x}$, or equivalent | M1 | |
| Obtain $y = \frac{e^{2x}}{2x+1}$, or equivalent expression for $y$ | A1 | ISW |

---
7 The variables $x$ and $y$ satisfy the differential equation

$$\mathrm { e } ^ { 2 x } \frac { \mathrm {~d} y } { \mathrm {~d} x } = 4 x y ^ { 2 }$$

and it is given that $y = 1$ when $x = 0$.\\
Solve the differential equation, obtaining an expression for $y$ in terms of $x$.\\

\hfill \mbox{\textit{CAIE P3 2021 Q7 [7]}}