CAIE P3 2021 November — Question 6 6 marks

Exam BoardCAIE
ModuleP3 (Pure Mathematics 3)
Year2021
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAddition & Double Angle Formulae
TypeProve identity then evaluate integral
DifficultyStandard +0.3 This is a straightforward two-part question requiring standard application of addition formulae and basic integration. Part (a) is guided algebra with sin(A±B) expansions, and part (b) involves routine integration of the simplified form with exact value evaluation. While it requires multiple steps, each step follows standard procedures with no novel insight needed, making it slightly easier than average.
Spec1.05l Double angle formulae: and compound angle formulae1.08i Integration by parts

6
  1. Using the expansions of \(\sin ( 3 x + 2 x )\) and \(\sin ( 3 x - 2 x )\), show that $$\frac { 1 } { 2 } ( \sin 5 x + \sin x ) \equiv \sin 3 x \cos 2 x$$
  2. Hence show that \(\int _ { 0 } ^ { \frac { 1 } { 4 } \pi } \sin 3 x \cos 2 x \mathrm {~d} x = \frac { 1 } { 5 } ( 3 - \sqrt { 2 } )\).

Question 6(a):
AnswerMarks Guidance
AnswerMark Guidance
State correct expansion of \(\sin(3x+2x)\) or \(\sin(3x-2x)\)B1
Substitute expansions in \(\frac{1}{2}(\sin 5x + \sin x)\), or equivalentM1
Simplify and obtain \(\frac{1}{2}(\sin 5x + \sin x) = \sin 3x \cos 2x\)A1 Obtain the given identity correctly
Total: 3 marks
Question 6(b):
AnswerMarks Guidance
AnswerMark Guidance
Obtain integral \(-\frac{1}{10}\cos 5x - \frac{1}{2}\cos x\), or equivalentB1
Substitute limits correctly in an expression of the form \(p\cos 5x + q\cos x\)M1 Correct limits and subtracted the right way around. Do not need values of trig functions for M1. Maximum one slip
Obtain \(\frac{1}{5}(3-\sqrt{2})\)A1 Substitute values and obtain the given answer following full, correct and exact working
Total: 3 marks
## Question 6(a):

| Answer | Mark | Guidance |
|--------|------|----------|
| State correct expansion of $\sin(3x+2x)$ or $\sin(3x-2x)$ | **B1** | |
| Substitute expansions in $\frac{1}{2}(\sin 5x + \sin x)$, or equivalent | **M1** | |
| Simplify and obtain $\frac{1}{2}(\sin 5x + \sin x) = \sin 3x \cos 2x$ | **A1** | Obtain the **given identity** correctly |

**Total: 3 marks**

## Question 6(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| Obtain integral $-\frac{1}{10}\cos 5x - \frac{1}{2}\cos x$, or equivalent | **B1** | |
| Substitute limits correctly in an expression of the form $p\cos 5x + q\cos x$ | **M1** | Correct limits and subtracted the right way around. Do not need values of trig functions for M1. Maximum one slip |
| Obtain $\frac{1}{5}(3-\sqrt{2})$ | **A1** | Substitute values and obtain the **given answer** following full, correct and exact working |

**Total: 3 marks**
6
\begin{enumerate}[label=(\alph*)]
\item Using the expansions of $\sin ( 3 x + 2 x )$ and $\sin ( 3 x - 2 x )$, show that

$$\frac { 1 } { 2 } ( \sin 5 x + \sin x ) \equiv \sin 3 x \cos 2 x$$
\item Hence show that $\int _ { 0 } ^ { \frac { 1 } { 4 } \pi } \sin 3 x \cos 2 x \mathrm {~d} x = \frac { 1 } { 5 } ( 3 - \sqrt { 2 } )$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P3 2021 Q6 [6]}}