OCR MEI Further Pure Core 2024 June — Question 4 4 marks

Exam BoardOCR MEI
ModuleFurther Pure Core (Further Pure Core)
Year2024
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVolumes of Revolution
TypeVolume requiring substitution or integration by parts
DifficultyStandard +0.8 This is a Further Maths volume of revolution question requiring integration of 1/(kΒ²+xΒ²), recognition of the arctan derivative, and solving Ο€[arctan(1) - 0] = 1 for k. The integration step requires knowing a non-standard integral form, and the algebraic manipulation is straightforward but the setup requires careful handling of the constant k throughout.
Spec4.08d Volumes of revolution: about x and y axes

4 The equation of a curve is \(\mathrm { y } = \frac { 1 } { \sqrt { \mathrm {~K} ^ { 2 } + \mathrm { x } ^ { 2 } } }\), where \(k\) is a positive constant. The region between the \(x\)-axis, the \(y\)-axis and the line \(x = k\) is rotated through \(2 \pi\) radians about the \(x\)-axis. Given that the volume of the solid of revolution formed is 1 unit \({ } ^ { 3 }\), find the exact value of \(k\).

Question 4:
AnswerMarks
4π‘˜ 1
[𝑉 =] πœ‹βˆ« [dπ‘₯]
π‘˜2+π‘₯2
0
π‘˜
1 π‘₯
πœ‹[ arctan( )]
π‘˜ π‘˜ 0
πœ‹2
[1 =]
4π‘˜
πœ‹2
π‘˜ =
AnswerMarks
4B1
B1
B1
B1
AnswerMarks
[4]1.1
1.1
1.1
AnswerMarks
3.1aIgnore limits and condone missing dπ‘₯. Multiplication by πœ‹
may appear later.
οƒͺ 1  x οƒΆοƒ·οƒΈ 
a r c t a n , ignore limits. Condone missing πœ‹.
k k
oe single term provided arctan terms evaluated
Question 4:
4 | π‘˜ 1
[𝑉 =] πœ‹βˆ« [dπ‘₯]
π‘˜2+π‘₯2
0
π‘˜
1 π‘₯
πœ‹[ arctan( )]
π‘˜ π‘˜ 0
πœ‹2
[1 =]
4π‘˜
πœ‹2
π‘˜ =
4 | B1
B1
B1
B1
[4] | 1.1
1.1
1.1
3.1a | Ignore limits and condone missing dπ‘₯. Multiplication by πœ‹
may appear later.
οƒͺ 1  x οƒΆοƒ·οƒΈ 
a r c t a n , ignore limits. Condone missing πœ‹.
k k
oe single term provided arctan terms evaluated
4 The equation of a curve is $\mathrm { y } = \frac { 1 } { \sqrt { \mathrm {~K} ^ { 2 } + \mathrm { x } ^ { 2 } } }$, where $k$ is a positive constant. The region between the $x$-axis, the $y$-axis and the line $x = k$ is rotated through $2 \pi$ radians about the $x$-axis.

Given that the volume of the solid of revolution formed is 1 unit ${ } ^ { 3 }$, find the exact value of $k$.

\hfill \mbox{\textit{OCR MEI Further Pure Core 2024 Q4 [4]}}