AQA FP2 2012 June — Question 1 7 marks

Exam BoardAQA
ModuleFP2 (Further Pure Mathematics 2)
Year2012
SessionJune
Marks7
PaperDownload PDF ↗
TopicHyperbolic functions
TypeSolve using substitution u = cosh x or u = sinh x
DifficultyStandard +0.3 This is a straightforward Further Maths question requiring standard techniques: sketching a basic hyperbolic function and solving a quadratic equation in cosh x using substitution u = cosh x, then applying the inverse hyperbolic function formula. While it's Further Maths content (inherently harder), the execution is routine with no novel problem-solving required—just direct application of learned methods.
Spec1.02f Solve quadratic equations: including in a function of unknown4.07a Hyperbolic definitions: sinh, cosh, tanh as exponentials4.07b Hyperbolic graphs: sketch and properties

1
  1. Sketch the curve \(y = \cosh x\).
  2. Solve the equation $$6 \cosh ^ { 2 } x - 7 \cosh x - 5 = 0$$ giving your answers in logarithmic form.

1
\begin{enumerate}[label=(\alph*)]
\item Sketch the curve $y = \cosh x$.
\item Solve the equation

$$6 \cosh ^ { 2 } x - 7 \cosh x - 5 = 0$$

giving your answers in logarithmic form.
\end{enumerate}

\hfill \mbox{\textit{AQA FP2 2012 Q1 [7]}}