Standard +0.3 This requires understanding the relationship between a function and its derivative (where f is increasing/decreasing, f' is positive/negative; stationary points of f correspond to zeros of f'), then sketching f'(x) from the given curve. It's a standard A-level pure maths skill testing conceptual understanding rather than calculation, slightly easier than average as it's primarily pattern recognition once the concept is grasped.
10 The diagram below shows the curve \(y = f ( x )\).
\includegraphics[max width=\textwidth, alt={}, center]{60e1e785-c34b-48ef-a63f-13a25fee186e-07_942_679_1500_242}
Sketch the graph of the gradient function, \(y = f ^ { \prime } ( x )\), on the copy of the diagram in the Printed Answer Booklet.
General shape of positive cubic; do not condone incorrect curvature
B1
\(y=x\) scores B0B1B0; use judgement on candidate's intention
Question 11a:
Answer
Marks
Guidance
\(x\cos x\) or unsimplified \(\sin x + x\cos x - \sin x\)
B1
Differentiating
Setting \(x\cos x = 1\)
M1
Finishing convincingly
A1
If no differentiation, M1 not available
Question 11b:
Answer
Marks
Guidance
Attempting to differentiate \(\frac{1}{x} - \cos x\) or \(x\cos x - 1\)
M1
Setting up iteration function with subscripts
A1
Must include subscripts
Choosing suitable starting value (accept values between 3.6 and 6.1)
M1
Root \(4.9172\) (4dp)
A1
Value outside range giving 4.9172 gets M1A1; wrong answer gets M0A0
Question 11c:
Answer
Marks
Comment more than just 'it is close to another root'
B1
Question 12a:
Answer
Marks
Guidance
Differentiating \(y\) wrt \(\theta\); may appear as \(dy/d\theta\) or numerator of \(dy/dx\)
M1
Ignore \(dx/d\theta\) unless used incorrectly in subsequent work
Putting expression \(= 0\) AND using \(\sin 2\theta = 2\sin\theta\cos\theta\) or \(\cos 2\theta\) in correct form; if \(dx/d\theta\) used incorrectly give M0
M1
Getting terms on one side and factorising
M1
Dividing through by \(\sin\theta\) costs all A marks
\(\sin\theta = 0\) and \(\cos\theta = -\frac{1}{2}\); 3rd and 4th M1s can be implied (BOD) by 2 correct solutions
M1
4th M1 dependent on previous M1
Exact values of \(\theta\) and coordinates (www marks)
A marks
e.g. \(\frac{4-\sqrt{3}}{2}\) for \(2-\frac{\sqrt{3}}{2}\), \(\frac{4+\sqrt{3}}{2}\) for \(2+\frac{\sqrt{3}}{2}\)
*Note: CHECK PAGE 11 for working*
Question 12b:
Answer
Marks
Guidance
\(x = 2\)
B1
Only acceptable answer
## Question 10:
| Crossing points at 0 and near $+2$ and $-2$ | B1 | |
| Rotational symmetry (or close to) | B1 | |
| General shape of positive cubic; do not condone incorrect curvature | B1 | $y=x$ scores B0B1B0; use judgement on candidate's intention |
## Question 11a:
| $x\cos x$ or unsimplified $\sin x + x\cos x - \sin x$ | B1 | Differentiating |
| Setting $x\cos x = 1$ | M1 | |
| Finishing convincingly | A1 | If no differentiation, M1 not available |
## Question 11b:
| Attempting to differentiate $\frac{1}{x} - \cos x$ or $x\cos x - 1$ | M1 | |
| Setting up iteration function **with subscripts** | A1 | Must include subscripts |
| Choosing suitable starting value (accept values between 3.6 and 6.1) | M1 | |
| Root $4.9172$ (4dp) | A1 | Value outside range giving 4.9172 gets M1A1; wrong answer gets M0A0 |
## Question 11c:
| Comment more than just 'it is close to another root' | B1 | |
## Question 12a:
| Differentiating $y$ wrt $\theta$; may appear as $dy/d\theta$ or numerator of $dy/dx$ | M1 | Ignore $dx/d\theta$ unless used incorrectly in subsequent work |
| Putting expression $= 0$ AND using $\sin 2\theta = 2\sin\theta\cos\theta$ or $\cos 2\theta$ in correct form; if $dx/d\theta$ used incorrectly give M0 | M1 | |
| Getting terms on one side and factorising | M1 | Dividing through by $\sin\theta$ costs all A marks |
| $\sin\theta = 0$ and $\cos\theta = -\frac{1}{2}$; 3rd and 4th M1s can be implied (BOD) by 2 correct solutions | M1 | 4th M1 dependent on previous M1 |
| Exact values of $\theta$ and coordinates (www marks) | A marks | e.g. $\frac{4-\sqrt{3}}{2}$ for $2-\frac{\sqrt{3}}{2}$, $\frac{4+\sqrt{3}}{2}$ for $2+\frac{\sqrt{3}}{2}$ |
*Note: CHECK PAGE 11 for working*
## Question 12b:
| $x = 2$ | B1 | Only acceptable answer |
10 The diagram below shows the curve $y = f ( x )$.\\
\includegraphics[max width=\textwidth, alt={}, center]{60e1e785-c34b-48ef-a63f-13a25fee186e-07_942_679_1500_242}
Sketch the graph of the gradient function, $y = f ^ { \prime } ( x )$, on the copy of the diagram in the Printed Answer Booklet.
\hfill \mbox{\textit{OCR MEI Paper 3 2024 Q10 [3]}}