OCR MEI Paper 3 2024 June — Question 10 3 marks

Exam BoardOCR MEI
ModulePaper 3 (Paper 3)
Year2024
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCurve Sketching
TypeCurve from derivative information
DifficultyStandard +0.3 This requires understanding the relationship between a function and its derivative (where f is increasing/decreasing, f' is positive/negative; stationary points of f correspond to zeros of f'), then sketching f'(x) from the given curve. It's a standard A-level pure maths skill testing conceptual understanding rather than calculation, slightly easier than average as it's primarily pattern recognition once the concept is grasped.
Spec1.07c Sketch gradient function: for given curve

10 The diagram below shows the curve \(y = f ( x )\). \includegraphics[max width=\textwidth, alt={}, center]{60e1e785-c34b-48ef-a63f-13a25fee186e-07_942_679_1500_242} Sketch the graph of the gradient function, \(y = f ^ { \prime } ( x )\), on the copy of the diagram in the Printed Answer Booklet.

Question 10:
AnswerMarks Guidance
Crossing points at 0 and near \(+2\) and \(-2\)B1
Rotational symmetry (or close to)B1
General shape of positive cubic; do not condone incorrect curvatureB1 \(y=x\) scores B0B1B0; use judgement on candidate's intention
Question 11a:
AnswerMarks Guidance
\(x\cos x\) or unsimplified \(\sin x + x\cos x - \sin x\)B1 Differentiating
Setting \(x\cos x = 1\)M1
Finishing convincinglyA1 If no differentiation, M1 not available
Question 11b:
AnswerMarks Guidance
Attempting to differentiate \(\frac{1}{x} - \cos x\) or \(x\cos x - 1\)M1
Setting up iteration function with subscriptsA1 Must include subscripts
Choosing suitable starting value (accept values between 3.6 and 6.1)M1
Root \(4.9172\) (4dp)A1 Value outside range giving 4.9172 gets M1A1; wrong answer gets M0A0
Question 11c:
AnswerMarks
Comment more than just 'it is close to another root'B1
Question 12a:
AnswerMarks Guidance
Differentiating \(y\) wrt \(\theta\); may appear as \(dy/d\theta\) or numerator of \(dy/dx\)M1 Ignore \(dx/d\theta\) unless used incorrectly in subsequent work
Putting expression \(= 0\) AND using \(\sin 2\theta = 2\sin\theta\cos\theta\) or \(\cos 2\theta\) in correct form; if \(dx/d\theta\) used incorrectly give M0M1
Getting terms on one side and factorisingM1 Dividing through by \(\sin\theta\) costs all A marks
\(\sin\theta = 0\) and \(\cos\theta = -\frac{1}{2}\); 3rd and 4th M1s can be implied (BOD) by 2 correct solutionsM1 4th M1 dependent on previous M1
Exact values of \(\theta\) and coordinates (www marks)A marks e.g. \(\frac{4-\sqrt{3}}{2}\) for \(2-\frac{\sqrt{3}}{2}\), \(\frac{4+\sqrt{3}}{2}\) for \(2+\frac{\sqrt{3}}{2}\)
*Note: CHECK PAGE 11 for working*
Question 12b:
AnswerMarks Guidance
\(x = 2\)B1 Only acceptable answer
## Question 10:
| Crossing points at 0 and near $+2$ and $-2$ | B1 | |
| Rotational symmetry (or close to) | B1 | |
| General shape of positive cubic; do not condone incorrect curvature | B1 | $y=x$ scores B0B1B0; use judgement on candidate's intention |

## Question 11a:
| $x\cos x$ or unsimplified $\sin x + x\cos x - \sin x$ | B1 | Differentiating |
| Setting $x\cos x = 1$ | M1 | |
| Finishing convincingly | A1 | If no differentiation, M1 not available |

## Question 11b:
| Attempting to differentiate $\frac{1}{x} - \cos x$ or $x\cos x - 1$ | M1 | |
| Setting up iteration function **with subscripts** | A1 | Must include subscripts |
| Choosing suitable starting value (accept values between 3.6 and 6.1) | M1 | |
| Root $4.9172$ (4dp) | A1 | Value outside range giving 4.9172 gets M1A1; wrong answer gets M0A0 |

## Question 11c:
| Comment more than just 'it is close to another root' | B1 | |

## Question 12a:
| Differentiating $y$ wrt $\theta$; may appear as $dy/d\theta$ or numerator of $dy/dx$ | M1 | Ignore $dx/d\theta$ unless used incorrectly in subsequent work |
| Putting expression $= 0$ AND using $\sin 2\theta = 2\sin\theta\cos\theta$ or $\cos 2\theta$ in correct form; if $dx/d\theta$ used incorrectly give M0 | M1 | |
| Getting terms on one side and factorising | M1 | Dividing through by $\sin\theta$ costs all A marks |
| $\sin\theta = 0$ and $\cos\theta = -\frac{1}{2}$; 3rd and 4th M1s can be implied (BOD) by 2 correct solutions | M1 | 4th M1 dependent on previous M1 |
| Exact values of $\theta$ and coordinates (www marks) | A marks | e.g. $\frac{4-\sqrt{3}}{2}$ for $2-\frac{\sqrt{3}}{2}$, $\frac{4+\sqrt{3}}{2}$ for $2+\frac{\sqrt{3}}{2}$ |

*Note: CHECK PAGE 11 for working*

## Question 12b:
| $x = 2$ | B1 | Only acceptable answer |
10 The diagram below shows the curve $y = f ( x )$.\\
\includegraphics[max width=\textwidth, alt={}, center]{60e1e785-c34b-48ef-a63f-13a25fee186e-07_942_679_1500_242}

Sketch the graph of the gradient function, $y = f ^ { \prime } ( x )$, on the copy of the diagram in the Printed Answer Booklet.

\hfill \mbox{\textit{OCR MEI Paper 3 2024 Q10 [3]}}