OCR MEI Paper 3 2024 June — Question 6 5 marks

Exam BoardOCR MEI
ModulePaper 3 (Paper 3)
Year2024
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard trigonometric equations
TypeConvert to quadratic in tan
DifficultyStandard +0.3 This is a standard trig equation requiring conversion of cot to tan, forming a quadratic in tan x, and solving within a given interval. While it involves multiple steps (rewriting cot x as 1/tan x, multiplying through, solving quadratic, finding angles), these are routine techniques for A-level. The algebraic manipulation is straightforward and the question type is common in textbooks, making it slightly easier than average.
Spec1.05h Reciprocal trig functions: sec, cosec, cot definitions and graphs1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05o Trigonometric equations: solve in given intervals

6 In this question you must show detailed reasoning. Solve the equation \(\tan x - 3 \cot x = 2\) for values of \(x\) in the interval \(0 ^ { \circ } \leqslant x \leqslant 360 ^ { \circ }\).

Question 6:
AnswerMarks Guidance
Multiplying through by \(\tan x\) (M1) OR replacing \(\tan x\) with \(\frac{\sin x}{\cos x}\) and \(\cot x\) with \(\frac{\cos x}{\sin x}\)M1 Two valid methods
Equation with 3 terms on one side and zero on otherM1
Solving 3-term equation AND getting both values of \(\tan x\) by valid method (factorisation, formula or completing square)M1
Any two correct anglesA1 Subject to at least M2
All roots, no additional solutions; \(72°/252°\) and over-specified answers e.g. \(71.565°/251.565°\) allowedA2 Subject to M3
## Question 6:
| Multiplying through by $\tan x$ (M1) OR replacing $\tan x$ with $\frac{\sin x}{\cos x}$ and $\cot x$ with $\frac{\cos x}{\sin x}$ | M1 | Two valid methods |
| Equation with 3 terms on one side and zero on other | M1 | |
| Solving 3-term equation AND getting both values of $\tan x$ by valid method (factorisation, formula or completing square) | M1 | |
| Any two correct angles | A1 | Subject to at least M2 |
| All roots, no additional solutions; $72°/252°$ and over-specified answers e.g. $71.565°/251.565°$ allowed | A2 | Subject to M3 |
6 In this question you must show detailed reasoning.
Solve the equation $\tan x - 3 \cot x = 2$ for values of $x$ in the interval $0 ^ { \circ } \leqslant x \leqslant 360 ^ { \circ }$.

\hfill \mbox{\textit{OCR MEI Paper 3 2024 Q6 [5]}}