| Exam Board | OCR MEI |
|---|---|
| Module | Paper 2 (Paper 2) |
| Year | 2020 |
| Session | November |
| Marks | 4 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Differentiating Transcendental Functions |
| Type | Differentiate trigonometric functions |
| Difficulty | Moderate -0.8 This is a straightforward differentiation question requiring the chain rule for sin(8x) and solving a simple trigonometric equation. Both parts are routine applications of standard techniques with no problem-solving insight needed, making it easier than average but not trivial since it requires correct application of the chain rule and knowledge of cosine values. |
| Spec | 1.07k Differentiate trig: sin(kx), cos(kx), tan(kx) |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| \(4 + 8\cos8x\) | M1* | differentiation with either term correct |
| A1 | all correct |
| Answer | Marks | Guidance |
|---|---|---|
| Answer | Marks | Guidance |
| attempt to solve their \(4 + 8\cos8x = 0\) | M1dep* | one intermediate step seen |
| \(\frac{\pi}{12}\) isw cao | A1 |
## Question 3:
### Part (a):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $4 + 8\cos8x$ | M1* | differentiation with either term correct |
| | A1 | all correct |
### Part (b):
| Answer | Marks | Guidance |
|--------|-------|----------|
| attempt to solve their $4 + 8\cos8x = 0$ | M1dep* | one intermediate step seen |
| $\frac{\pi}{12}$ isw cao | A1 | |
---3 You are given that $y = 4 x + \sin 8 x$.
\begin{enumerate}[label=(\alph*)]
\item Find $\frac { \mathrm { dy } } { \mathrm { dx } }$.
\item Find the smallest positive value of $x$ for which $\frac { \mathrm { dy } } { \mathrm { dx } } = 0$, giving your answer in an exact form.
\end{enumerate}
\hfill \mbox{\textit{OCR MEI Paper 2 2020 Q3 [4]}}