OCR MEI Paper 2 2024 June — Question 6 5 marks

Exam BoardOCR MEI
ModulePaper 2 (Paper 2)
Year2024
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDiscrete Probability Distributions
TypeOne unknown from sum constraint only
DifficultyEasy -1.8 This is a very routine probability distribution question requiring only basic recall: (a) uses the fact that probabilities sum to 1 to find a single unknown (0.2 + a + 3a + 0.4 = 1 gives a = 0.1), (b) adds two probabilities, and (c) applies independence to find P(X₁ + X₂ = 3). All three parts are standard textbook exercises with no problem-solving or insight required, making this significantly easier than average A-level questions.
Spec2.04a Discrete probability distributions

6 The probability distribution of the discrete random variable \(X\) is shown in the table.
\(x\)0123
\(\mathrm { P } ( \mathrm { X } = \mathrm { x } )\)0.2\(a\)\(3 a\)0.4
  1. Calculate the value of the constant \(a\).
  2. A single value of \(X\) is chosen at random. Find the probability that the value is an odd number.
  3. Two independent values of \(X\) are chosen at random. Calculate the probability that the total of the two values is 3 .

Question 6:
Part (a):
AnswerMarks Guidance
AnswerMarks Guidance
\(a = 0.1\)B1
Part (b):
AnswerMarks Guidance
AnswerMarks Guidance
\(0.5\)B1FT FT their \(0.1 + 0.4\); \(0 <\) their \(a <\) their \(3a < 1\)
Part (c):
AnswerMarks Guidance
AnswerMarks Guidance
\(0.2 \times 0.4\) oe or their \(3a \times\) their \(a\) oe seenB1 \(0.2 \times 0.4\) or \(0.3 \times 0.1\)
\(2 \times (0.2 \times 0.4 + \text{their } 3a \times \text{their } a)\)M1 NB \(2 \times (0.2 \times 0.4 + 0.3 \times 0.1)\); allow omission of 2; may be implied by 0.11
\(0.22\)A1
## Question 6:

### Part (a):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $a = 0.1$ | B1 | |

### Part (b):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $0.5$ | B1FT | FT their $0.1 + 0.4$; $0 <$ their $a <$ their $3a < 1$ |

### Part (c):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $0.2 \times 0.4$ oe or their $3a \times$ their $a$ oe seen | B1 | $0.2 \times 0.4$ **or** $0.3 \times 0.1$ |
| $2 \times (0.2 \times 0.4 + \text{their } 3a \times \text{their } a)$ | M1 | **NB** $2 \times (0.2 \times 0.4 + 0.3 \times 0.1)$; allow omission of 2; may be implied by 0.11 |
| $0.22$ | A1 | |

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6 The probability distribution of the discrete random variable $X$ is shown in the table.

\begin{center}
\begin{tabular}{ | l | l | l | l | l | }
\hline
$x$ & 0 & 1 & 2 & 3 \\
\hline
$\mathrm { P } ( \mathrm { X } = \mathrm { x } )$ & 0.2 & $a$ & $3 a$ & 0.4 \\
\hline
\end{tabular}
\end{center}
\begin{enumerate}[label=(\alph*)]
\item Calculate the value of the constant $a$.
\item A single value of $X$ is chosen at random.

Find the probability that the value is an odd number.
\item Two independent values of $X$ are chosen at random.

Calculate the probability that the total of the two values is 3 .
\end{enumerate}

\hfill \mbox{\textit{OCR MEI Paper 2 2024 Q6 [5]}}