Easy -1.2 This is a straightforward application of two standard transformations to an exponential function. Students need only recall and apply the transformation rules: translation by (3,0) gives e^(x-3), then stretch factor 2 parallel to y-axis gives 2e^(x-3). No problem-solving or insight required, just direct application of memorized transformation rules.
2 The equation of a curve is \(y = e ^ { x }\). The curve is subject to a translation \(\binom { 3 } { 0 }\) and a stretch scale factor 2 parallel to the \(y\)-axis.
Write down the equation of the new curve.
e.g. M1 for \(2e^x - 3\) or \(e^{\frac{1}{2}x-3}\)
\(y = 2e^{x-3}\) or \(f(x) = 2e^{x-3}\) oe isw
A1
must be an equation; B2 for correct answer with no working
## Question 2:
$2e^x$ soi **or** $-3$ seen in exponent | M1 | e.g. M1 for $2e^x - 3$ **or** $e^{\frac{1}{2}x-3}$
$y = 2e^{x-3}$ **or** $f(x) = 2e^{x-3}$ oe isw | A1 | must be an equation; **B2** for correct answer with no working
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2 The equation of a curve is $y = e ^ { x }$. The curve is subject to a translation $\binom { 3 } { 0 }$ and a stretch scale factor 2 parallel to the $y$-axis.
Write down the equation of the new curve.
\hfill \mbox{\textit{OCR MEI Paper 2 2024 Q2 [2]}}