Easy -1.2 This is a straightforward application of Newton's second law (F=ma) followed by a single SUVAT equation. It requires only two steps: find acceleration from net force, then use v=u+at. No problem-solving insight needed, just direct formula application with clearly given values.
5 A car of mass 1200 kg travels from rest along a straight horizontal road. The driving force is 4000 N and the total of all resistances to motion is 800 N .
Calculate the velocity of the car after 9 seconds.
Both forces present; allow sign errors; allow \(3200=1200a\) seen
\(a=\frac{8}{3}\) m s\(^{-2}\)
A1
Soi
Using \(v=u+at\) gives \(v=\frac{8}{3}\times 9=24\) m s\(^{-1}\)
M1
Using suvat equation(s) leading to a value for \(v\)
A1 [4]
FT their \(a\)
## Question 5:
| Answer | Marks | Guidance |
|--------|-------|----------|
| N2L gives $4000-800=1200a$ | M1 | Both forces present; allow sign errors; allow $3200=1200a$ seen |
| $a=\frac{8}{3}$ m s$^{-2}$ | A1 | Soi |
| Using $v=u+at$ gives $v=\frac{8}{3}\times 9=24$ m s$^{-1}$ | M1 | Using suvat equation(s) leading to a value for $v$ |
| | A1 [4] | FT their $a$ |
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5 A car of mass 1200 kg travels from rest along a straight horizontal road. The driving force is 4000 N and the total of all resistances to motion is 800 N .\\
Calculate the velocity of the car after 9 seconds.
\hfill \mbox{\textit{OCR MEI Paper 1 2019 Q5 [4]}}