AQA FP3 2014 June — Question 2 8 marks

Exam BoardAQA
ModuleFP3 (Further Pure Mathematics 3)
Year2014
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFirst order differential equations (integrating factor)
TypeStandard linear first order - constant coefficients
DifficultyStandard +0.8 This is a Further Maths FP3 question requiring the method of undetermined coefficients to find a particular integral, then solving using integrating factor and applying initial conditions. While the techniques are standard for Further Maths, the combination of finding a particular integral with trigonometric terms, computing the complementary function, and applying boundary conditions makes this moderately challenging, requiring careful algebraic manipulation across multiple steps.
Spec4.10c Integrating factor: first order equations

2
  1. Find the values of the constants \(a\), \(b\) and \(c\) for which \(a + b \sin 2 x + c \cos 2 x\) is a particular integral of the differential equation $$\frac { \mathrm { d } y } { \mathrm {~d} x } + 4 y = 20 - 20 \cos 2 x$$ [4 marks]
  2. Hence find the solution of this differential equation, given that \(y = 4\) when \(x = 0\).
    [0pt] [4 marks]
    \includegraphics[max width=\textwidth, alt={}]{0eb3e96e-528c-4a99-b164-31cc865f0d68-04_1974_1709_733_153}

Question 2(a)
[4 marks]
M1: Substitute \(y = a + b\sin 2x + c\cos 2x\) into differential equation
M1: Find \(\frac{dy}{dx} = 2b\cos 2x - 2c\sin 2x\)
M1: Equate coefficients of constant, \(\sin 2x\) and \(\cos 2x\) terms
A1: Correct values \(a = 5\), \(b = 0\), \(c = -5\)
Question 2(b)
[4 marks]
M1: Find complementary function \(y_c = Ae^{-4x}\)
M1: State particular integral \(y_p = 5 - 5\cos 2x\)
M1: General solution \(y = Ae^{-4x} + 5 - 5\cos 2x\)
A1: Apply initial condition \(y = 4\) when \(x = 0\) to find \(A = -1\)
A1: Final solution \(y = -e^{-4x} + 5 - 5\cos 2x\)
## Question 2(a)
[4 marks]

M1: Substitute $y = a + b\sin 2x + c\cos 2x$ into differential equation

M1: Find $\frac{dy}{dx} = 2b\cos 2x - 2c\sin 2x$

M1: Equate coefficients of constant, $\sin 2x$ and $\cos 2x$ terms

A1: Correct values $a = 5$, $b = 0$, $c = -5$

## Question 2(b)
[4 marks]

M1: Find complementary function $y_c = Ae^{-4x}$

M1: State particular integral $y_p = 5 - 5\cos 2x$

M1: General solution $y = Ae^{-4x} + 5 - 5\cos 2x$

A1: Apply initial condition $y = 4$ when $x = 0$ to find $A = -1$

A1: Final solution $y = -e^{-4x} + 5 - 5\cos 2x$
2
\begin{enumerate}[label=(\alph*)]
\item Find the values of the constants $a$, $b$ and $c$ for which $a + b \sin 2 x + c \cos 2 x$ is a particular integral of the differential equation

$$\frac { \mathrm { d } y } { \mathrm {~d} x } + 4 y = 20 - 20 \cos 2 x$$

[4 marks]
\item Hence find the solution of this differential equation, given that $y = 4$ when $x = 0$.\\[0pt]
[4 marks]

\begin{center}
\includegraphics[max width=\textwidth, alt={}]{0eb3e96e-528c-4a99-b164-31cc865f0d68-04_1974_1709_733_153}
\end{center}
\end{enumerate}

\hfill \mbox{\textit{AQA FP3 2014 Q2 [8]}}