CAIE FP2 2016 November — Question 6 7 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2016
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicT-tests (unknown variance)
TypeSingle sample t-test
DifficultyStandard +0.3 This is a straightforward one-sample t-test with all values provided. Students need to calculate the test statistic using the given sample mean, hypothesized mean, and sum of squared deviations, then compare to critical values. It requires standard procedure application with no conceptual challenges or novel problem-solving, making it slightly easier than average.
Spec5.05b Unbiased estimates: of population mean and variance5.05c Hypothesis test: normal distribution for population mean

6 A random sample of 8 observations of a normal random variable \(X\) has mean \(\bar { x }\), where $$\bar { x } = 6.246 \quad \text { and } \quad \Sigma ( x - \bar { x } ) ^ { 2 } = 0.784$$ Test, at the \(5 \%\) significance level, whether the population mean of \(X\) is less than 6.44.

Question 6:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(s^2 = 0.784/7 = 0.112\) or \(14/125\) or \(0.3347^2\)M1 Allow biased: \(0.098\) or \(0.3130^2\)
\(H_0: \mu = 6.44,\ H_1: \mu < 6.44\)B1 State hypotheses
\(t = (6.44 - \bar{x})/(s/\sqrt{8}) = 1.64\)M1 A1 Calculate value of \(t\), either sign, to 3 s.f.
\(t_{7,\ 0.95} = 1.89[5]\)B1 State or use correct tabular \(t\)-value to 3 s.f.
Accept \(H_0\) if \(t <\) tabular valueM1 State or imply valid method for conclusion
\(1.64 < 1.89\) so popln. mean not less than \(6.44\)A1 Conclusion (AEF, requires both values correct)
# Question 6:

| Answer/Working | Marks | Guidance |
|---|---|---|
| $s^2 = 0.784/7 = 0.112$ or $14/125$ or $0.3347^2$ | M1 | Allow biased: $0.098$ or $0.3130^2$ |
| $H_0: \mu = 6.44,\ H_1: \mu < 6.44$ | B1 | State hypotheses |
| $t = (6.44 - \bar{x})/(s/\sqrt{8}) = 1.64$ | M1 A1 | Calculate value of $t$, either sign, to 3 s.f. |
| $t_{7,\ 0.95} = 1.89[5]$ | B1 | State or use correct tabular $t$-value to 3 s.f. |
| Accept $H_0$ if $t <$ tabular value | M1 | State or imply valid method for conclusion |
| $1.64 < 1.89$ so popln. mean not less than $6.44$ | A1 | Conclusion (AEF, requires both values correct) |

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6 A random sample of 8 observations of a normal random variable $X$ has mean $\bar { x }$, where

$$\bar { x } = 6.246 \quad \text { and } \quad \Sigma ( x - \bar { x } ) ^ { 2 } = 0.784$$

Test, at the $5 \%$ significance level, whether the population mean of $X$ is less than 6.44.

\hfill \mbox{\textit{CAIE FP2 2016 Q6 [7]}}