CAIE FP2 2011 June — Question 2 7 marks

Exam BoardCAIE
ModuleFP2 (Further Pure Mathematics 2)
Year2011
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSimple Harmonic Motion
TypeSmall oscillations with elastic strings/springs
DifficultyChallenging +1.2 This is a standard Further Maths mechanics question requiring small-angle approximation with elastic strings. While it involves multiple steps (finding tension using Hooke's law, binomial approximation, verifying SHM conditions, and finding period), the techniques are well-practiced in FP2/FM2 syllabi. The small oscillations approximation is a routine application, making this moderately above average difficulty but not requiring novel insight.
Spec4.10f Simple harmonic motion: x'' = -omega^2 x6.02g Hooke's law: T = k*x or T = lambda*x/l

2 A particle of mass \(m\) is attached to the mid-point of a light elastic string. The string is stretched between two points \(A\) and \(B\) on a smooth horizontal surface, where \(A B = 2 a\). The string has modulus of elasticity \(\lambda\) and natural length \(2 l\), where \(l < a\). The particle is in motion on the surface along a line passing through the mid-point of \(A B\) and perpendicular to \(A B\). When the displacement of the particle from \(A B\) is \(x\), the tension in the string is \(T\). Given that \(x\) is small enough for \(x ^ { 2 }\) to be neglected, show that $$T = \frac { \lambda } { l } ( a - l )$$ The particle is slightly disturbed from its equilibrium position. Show that it will perform approximate simple harmonic motion and find the period of the motion.

Question 2:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(T = \lambda\{2\sqrt{(a^2 + x^2)} - 2l\}/2l\)M1 A1 Find \(T\) by Hooke's Law for whole [or half] string
\(= (\lambda/l)(a - l)\) A.G.A1 Neglect \(x^2\): [M0 for motion along string]
\(md^2x/dt^2 = -2Tx/\sqrt{(a^2 + x^2)}\)M1 Find eqn of motion at general point
\(-(2T/ma)x\) or \(-\{2\lambda(a-l)/alm\}x\)M1 A1 Neglect \(x^2\) to give SHM eqn for \(d^2x/dt^2\)
\(2\pi\sqrt{\{alm/2\lambda(a-l)\}}\)B1 State period using \(2\pi/\omega\) (A.E.F.)
\(d^2x/dt^2 = -2\lambda x/lm\)(B1) S.R. Motion along string earns max 1 mark
M.R. Vertical motion loses one A/B mark. Total: [7]
## Question 2:

| Answer/Working | Marks | Guidance |
|---|---|---|
| $T = \lambda\{2\sqrt{(a^2 + x^2)} - 2l\}/2l$ | M1 A1 | Find $T$ by Hooke's Law for whole [or half] string |
| $= (\lambda/l)(a - l)$ **A.G.** | A1 | Neglect $x^2$: [M0 for motion along string] |
| $md^2x/dt^2 = -2Tx/\sqrt{(a^2 + x^2)}$ | M1 | Find eqn of motion at general point |
| $-(2T/ma)x$ or $-\{2\lambda(a-l)/alm\}x$ | M1 A1 | Neglect $x^2$ to give SHM eqn for $d^2x/dt^2$ |
| $2\pi\sqrt{\{alm/2\lambda(a-l)\}}$ | B1 | State period using $2\pi/\omega$ (A.E.F.) |
| $d^2x/dt^2 = -2\lambda x/lm$ | (B1) | **S.R.** Motion along string earns max 1 mark |

**M.R.** Vertical motion loses one A/B mark. **Total: [7]**

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2 A particle of mass $m$ is attached to the mid-point of a light elastic string. The string is stretched between two points $A$ and $B$ on a smooth horizontal surface, where $A B = 2 a$. The string has modulus of elasticity $\lambda$ and natural length $2 l$, where $l < a$. The particle is in motion on the surface along a line passing through the mid-point of $A B$ and perpendicular to $A B$. When the displacement of the particle from $A B$ is $x$, the tension in the string is $T$. Given that $x$ is small enough for $x ^ { 2 }$ to be neglected, show that

$$T = \frac { \lambda } { l } ( a - l )$$

The particle is slightly disturbed from its equilibrium position. Show that it will perform approximate simple harmonic motion and find the period of the motion.

\hfill \mbox{\textit{CAIE FP2 2011 Q2 [7]}}