CAIE FP1 2012 November — Question 2 6 marks

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2012
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCentre of Mass 2
TypeCentre of mass of lamina by integration
DifficultyStandard +0.3 This is a straightforward application of standard integration formulas for mean value and centroid. The function y = 2x^(1/2) integrates easily, and both parts require only direct substitution into memorized formulas with no conceptual challenges or problem-solving insight needed.
Spec1.08d Evaluate definite integrals: between limits4.08f Integrate using partial fractions

2 The curve \(C\) has equation \(y = 2 x ^ { \frac { 1 } { 2 } }\) for \(0 \leqslant x \leqslant 4\). Find
  1. the mean value of \(y\) with respect to \(x\) for \(0 \leqslant x \leqslant 4\),
  2. the \(y\)-coordinate of the centroid of the region enclosed by \(C\), the line \(x = 4\) and the \(x\)-axis.

Question 2(i):
AnswerMarks Guidance
Working/AnswerMark Guidance
\(\dfrac{\displaystyle\int_0^4 2x^{\frac{1}{2}}\,dx}{4}\)M1 Uses formula for mean value
\(= \left[\frac{1}{3}x^{\frac{3}{2}}\right]_0^4 = \frac{8}{3}\)M1A1 Integrates; part total 3
Question 2(ii):
AnswerMarks Guidance
Working/AnswerMark Guidance
\(\dfrac{\frac{1}{2}\displaystyle\int_0^4 4x\,dx}{\displaystyle\int_0^4 2x^{\frac{1}{2}}\,dx}\)M1 Uses formula for \(y\)-coordinate
\(= \dfrac{\left[x^2\right]_0^4}{\left[\frac{4}{3}x^{\frac{3}{2}}\right]_0^4} = \frac{16\times 3}{32} = \frac{3}{2}\)M1A1 Integrates; part total 3; Total [6]
## Question 2(i):

| Working/Answer | Mark | Guidance |
|---|---|---|
| $\dfrac{\displaystyle\int_0^4 2x^{\frac{1}{2}}\,dx}{4}$ | M1 | Uses formula for mean value |
| $= \left[\frac{1}{3}x^{\frac{3}{2}}\right]_0^4 = \frac{8}{3}$ | M1A1 | Integrates; part total 3 |

## Question 2(ii):

| Working/Answer | Mark | Guidance |
|---|---|---|
| $\dfrac{\frac{1}{2}\displaystyle\int_0^4 4x\,dx}{\displaystyle\int_0^4 2x^{\frac{1}{2}}\,dx}$ | M1 | Uses formula for $y$-coordinate |
| $= \dfrac{\left[x^2\right]_0^4}{\left[\frac{4}{3}x^{\frac{3}{2}}\right]_0^4} = \frac{16\times 3}{32} = \frac{3}{2}$ | M1A1 | Integrates; part total 3; **Total [6]** |

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2 The curve $C$ has equation $y = 2 x ^ { \frac { 1 } { 2 } }$ for $0 \leqslant x \leqslant 4$. Find\\
(i) the mean value of $y$ with respect to $x$ for $0 \leqslant x \leqslant 4$,\\
(ii) the $y$-coordinate of the centroid of the region enclosed by $C$, the line $x = 4$ and the $x$-axis.

\hfill \mbox{\textit{CAIE FP1 2012 Q2 [6]}}