CAIE FP1 2016 June — Question 8 11 marks

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2016
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVectors: Lines & Planes
TypeLine of intersection of planes
DifficultyStandard +0.8 This is a substantial three-part Further Maths question requiring: (1) finding a plane equation from three points using cross product of direction vectors, (2) calculating angle between planes using normal vectors, and (3) finding line of intersection by solving simultaneous equations and expressing parametrically. While each technique is standard for FM students, the combination of multiple steps and the need for accurate vector manipulation throughout makes this moderately challenging.
Spec4.04a Line equations: 2D and 3D, cartesian and vector forms4.04b Plane equations: cartesian and vector forms4.04d Angles: between planes and between line and plane

8 Find a cartesian equation of the plane \(\Pi _ { 1 }\) passing through the points with coordinates \(( 2 , - 1,3 )\), \(( 4,2 , - 5 )\) and \(( - 1,3 , - 2 )\). The plane \(\Pi _ { 2 }\) has cartesian equation \(3 x - y + 2 z = 5\). Find the acute angle between \(\Pi _ { 1 }\) and \(\Pi _ { 2 }\). Find a vector equation of the line of intersection of the planes \(\Pi _ { 1 }\) and \(\Pi _ { 2 }\).

Question 8:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\overrightarrow{AB} \times \overrightarrow{AC} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 2 & 3 & -8 \\ -3 & 4 & -5 \end{vmatrix} = \begin{pmatrix} 17 \\ 34 \\ 17 \end{pmatrix} \sim \begin{pmatrix} 1 \\ 2 \\ 1 \end{pmatrix}\)M1 A1
\(x + 2y + z = \text{const} \Rightarrow \text{const} = 2-2+3 = 3\) (using a point) \(\Rightarrow x+2y+z=3\)M1, A1 [4]
\(\sqrt{9+1+4}\sqrt{1+4+1}\cos\theta = \begin{pmatrix}1\\2\\1\end{pmatrix}\cdot\begin{pmatrix}3\\-1\\2\end{pmatrix} \Rightarrow \cos\theta = \frac{3}{\sqrt{14}\sqrt{6}} = \frac{3}{\sqrt{84}}\)M1 M1
\(\Rightarrow \theta = 70.9°\) or \(1.24\) radiansA1 [3]
Direction of line of intersection is \(\begin{vmatrix}\mathbf{i}&\mathbf{j}&\mathbf{k}\\1&2&1\\3&-1&2\end{vmatrix} = \begin{pmatrix}5\\1\\-7\end{pmatrix}\)M1A1
Finds point common to both planes e.g. \((-1,0,4)\) or \(\left(\frac{13}{7},\frac{4}{7},0\right)\) or \(\left(0,\frac{1}{5},\frac{13}{5}\right)\)M1
Equation of line of intersection is e.g. \(\mathbf{r} = \begin{pmatrix}-1\\0\\4\end{pmatrix} + t\begin{pmatrix}5\\1\\-7\end{pmatrix}\)A1\(\checkmark\) [4]
# Question 8:

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\overrightarrow{AB} \times \overrightarrow{AC} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ 2 & 3 & -8 \\ -3 & 4 & -5 \end{vmatrix} = \begin{pmatrix} 17 \\ 34 \\ 17 \end{pmatrix} \sim \begin{pmatrix} 1 \\ 2 \\ 1 \end{pmatrix}$ | M1 A1 | |
| $x + 2y + z = \text{const} \Rightarrow \text{const} = 2-2+3 = 3$ (using a point) $\Rightarrow x+2y+z=3$ | M1, A1 [4] | |
| $\sqrt{9+1+4}\sqrt{1+4+1}\cos\theta = \begin{pmatrix}1\\2\\1\end{pmatrix}\cdot\begin{pmatrix}3\\-1\\2\end{pmatrix} \Rightarrow \cos\theta = \frac{3}{\sqrt{14}\sqrt{6}} = \frac{3}{\sqrt{84}}$ | M1 M1 | |
| $\Rightarrow \theta = 70.9°$ or $1.24$ radians | A1 [3] | |
| Direction of line of intersection is $\begin{vmatrix}\mathbf{i}&\mathbf{j}&\mathbf{k}\\1&2&1\\3&-1&2\end{vmatrix} = \begin{pmatrix}5\\1\\-7\end{pmatrix}$ | M1A1 | |
| Finds point common to both planes e.g. $(-1,0,4)$ or $\left(\frac{13}{7},\frac{4}{7},0\right)$ or $\left(0,\frac{1}{5},\frac{13}{5}\right)$ | M1 | |
| Equation of line of intersection is e.g. $\mathbf{r} = \begin{pmatrix}-1\\0\\4\end{pmatrix} + t\begin{pmatrix}5\\1\\-7\end{pmatrix}$ | A1$\checkmark$ [4] | |

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8 Find a cartesian equation of the plane $\Pi _ { 1 }$ passing through the points with coordinates $( 2 , - 1,3 )$, $( 4,2 , - 5 )$ and $( - 1,3 , - 2 )$.

The plane $\Pi _ { 2 }$ has cartesian equation $3 x - y + 2 z = 5$. Find the acute angle between $\Pi _ { 1 }$ and $\Pi _ { 2 }$.

Find a vector equation of the line of intersection of the planes $\Pi _ { 1 }$ and $\Pi _ { 2 }$.

\hfill \mbox{\textit{CAIE FP1 2016 Q8 [11]}}