CAIE FP1 2008 June — Question 1 4 marks

Exam BoardCAIE
ModuleFP1 (Further Pure Mathematics 1)
Year2008
SessionJune
Marks4
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Mark schemeDownload PDF ↗
TopicCentre of Mass 2
TypeProve standard centre of mass formula
DifficultyStandard +0.8 This is a Further Maths question requiring students to derive a standard result (centroid of a cone) using integration of volumes of revolution. It demands setting up the integral for the first moment correctly, applying the volume formula, and algebraic manipulation to reach the given result. While the setup is moderately challenging, the integration itself is routine and the result is provided to verify against.
Spec4.08d Volumes of revolution: about x and y axes6.04d Integration: for centre of mass of laminas/solids

1 The finite region enclosed by the line \(y = k x\), where \(k\) is a positive constant, the \(x\)-axis for \(0 \leqslant x \leqslant h\), and the line \(x = h\) is rotated through 1 complete revolution about the \(x\)-axis. Prove by integration that the centroid of the resulting cone is at a distance \(\frac { 3 } { 4 } h\) from the origin \(O\).
[0pt] [The volume of a cone of height \(h\) and base radius \(r\) is \(\frac { 1 } { 3 } \pi r ^ { 2 } h\).]

AnswerMarks
\(\int_0^h xy^2 dx = \int_0^h x(rx/h)^2 dx\)M1
\(= ... = r^2 h^3/4\) (Q)A1
\(\bar{x} = Q/V = 3h/4\)M1A1
OR \((1/3)\pi rK^2 h^3\bar{x} = \int_0^h \pi rK^2 x^3 dx\)M1M1
\((1/3)h^3\bar{x} = [x^4/4]_0^h\)A1
\(\bar{x} = 3h/4\) (AG)A1
$\int_0^h xy^2 dx = \int_0^h x(rx/h)^2 dx$ | M1 |
$= ... = r^2 h^3/4$ (Q) | A1 |
$\bar{x} = Q/V = 3h/4$ | M1A1 |
**OR** $(1/3)\pi rK^2 h^3\bar{x} = \int_0^h \pi rK^2 x^3 dx$ | M1M1 |
$(1/3)h^3\bar{x} = [x^4/4]_0^h$ | A1 |
$\bar{x} = 3h/4$ (AG) | A1 |
1 The finite region enclosed by the line $y = k x$, where $k$ is a positive constant, the $x$-axis for $0 \leqslant x \leqslant h$, and the line $x = h$ is rotated through 1 complete revolution about the $x$-axis. Prove by integration that the centroid of the resulting cone is at a distance $\frac { 3 } { 4 } h$ from the origin $O$.\\[0pt]
[The volume of a cone of height $h$ and base radius $r$ is $\frac { 1 } { 3 } \pi r ^ { 2 } h$.]

\hfill \mbox{\textit{CAIE FP1 2008 Q1 [4]}}