Edexcel AEA 2007 June — Question 5 15 marks

Exam BoardEdexcel
ModuleAEA (Advanced Extension Award)
Year2007
SessionJune
Marks15
PaperDownload PDF ↗
TopicSequences and Series
TypeInfinite Products and Nested Sequences
DifficultyChallenging +1.8 This AEA question involves geometric sequences with fractal-like snowflakes requiring pattern recognition and series summation. Parts (a)-(d) involve finding recurrence patterns and limits, while (e)-(f) require summing infinite geometric series to find bounded areas. The multi-step nature, need for geometric insight, and infinite series work place it well above average difficulty, though the techniques are ultimately standard for AEA level.
Spec1.04h Arithmetic sequences: nth term and sum formulae1.04i Geometric sequences: nth term and finite series sum1.04j Sum to infinity: convergent geometric series |r|<11.05k Further identities: sec^2=1+tan^2 and cosec^2=1+cot^2

5. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{f2290882-b9a4-43ec-a38f-c44d46477242-4_493_1324_279_367} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} Figure 1 shows part of a sequence \(S _ { 1 } , S _ { 2 } , S _ { 3 } , \ldots\), of model snowflakes. The first term \(S _ { 1 }\) consists of a single square of side \(a\). To obtain \(S _ { 2 }\), the middle third of each edge is replaced with a new square, of side \(\frac { a } { 3 }\), as shown in Figure 1 . Subsequent terms are obtained by replacing the middle third of each external edge of a new square formed in the previous snowflake, by a square \(\frac { 1 } { 3 }\) of the size, as illustrated by \(S _ { 3 }\) in Figure 1.
  1. Deduce that to form \(S _ { 4 } , 36\) new squares of side \(\frac { a } { 27 }\) must be added to \(S _ { 3 }\).
  2. Show that the perimeters of \(S _ { 2 }\) and \(S _ { 3 }\) are \(\frac { 20 a } { 3 }\) and \(\frac { 28 a } { 3 }\) respectively.
  3. Find the perimeter of \(S _ { n }\).
  4. Describe what happens to the perimeter of \(S _ { n }\) as \(n\) increases.
  5. Find the areas of \(S _ { 1 } , S _ { 2 }\) and \(S _ { 3 }\).
  6. Find the smallest value of the constant \(S\) such that the area of \(S _ { n } < S\), for all values of \(n\). \includegraphics[max width=\textwidth, alt={}, center]{f2290882-b9a4-43ec-a38f-c44d46477242-5_590_1041_283_588} Figure 2 shows a sketch of the curve \(C\) with equation \(y = \tan \frac { t } { 2 } , \quad 0 \leq t \leq \frac { \pi } { 2 }\).
    The point \(P\) on \(C\) has coordinates \(\left( x , \tan \frac { x } { 2 } \right)\).
    The vertices of rectangle \(R\) are at \(( x , 0 ) , \left( \frac { x } { 2 } , 0 \right) , \left( \frac { x } { 2 } , \tan \frac { x } { 2 } \right)\) and \(\left( x , \tan \frac { x } { 2 } \right)\) as shown in Figure 2.

5.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{f2290882-b9a4-43ec-a38f-c44d46477242-4_493_1324_279_367}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{center}
\end{figure}

Figure 1 shows part of a sequence $S _ { 1 } , S _ { 2 } , S _ { 3 } , \ldots$, of model snowflakes. The first term $S _ { 1 }$ consists of a single square of side $a$. To obtain $S _ { 2 }$, the middle third of each edge is replaced with a new square, of side $\frac { a } { 3 }$, as shown in Figure 1 . Subsequent terms are obtained by replacing the middle third of each external edge of a new square formed in the previous snowflake, by a square $\frac { 1 } { 3 }$ of the size, as illustrated by $S _ { 3 }$ in Figure 1.
\begin{enumerate}[label=(\alph*)]
\item Deduce that to form $S _ { 4 } , 36$ new squares of side $\frac { a } { 27 }$ must be added to $S _ { 3 }$.
\item Show that the perimeters of $S _ { 2 }$ and $S _ { 3 }$ are $\frac { 20 a } { 3 }$ and $\frac { 28 a } { 3 }$ respectively.
\item Find the perimeter of $S _ { n }$.
\item Describe what happens to the perimeter of $S _ { n }$ as $n$ increases.
\item Find the areas of $S _ { 1 } , S _ { 2 }$ and $S _ { 3 }$.
\item Find the smallest value of the constant $S$ such that the area of $S _ { n } < S$, for all values of $n$.\\
\includegraphics[max width=\textwidth, alt={}, center]{f2290882-b9a4-43ec-a38f-c44d46477242-5_590_1041_283_588}

Figure 2 shows a sketch of the curve $C$ with equation $y = \tan \frac { t } { 2 } , \quad 0 \leq t \leq \frac { \pi } { 2 }$.\\
The point $P$ on $C$ has coordinates $\left( x , \tan \frac { x } { 2 } \right)$.\\
The vertices of rectangle $R$ are at $( x , 0 ) , \left( \frac { x } { 2 } , 0 \right) , \left( \frac { x } { 2 } , \tan \frac { x } { 2 } \right)$ and $\left( x , \tan \frac { x } { 2 } \right)$ as shown in Figure 2.
\end{enumerate}

\hfill \mbox{\textit{Edexcel AEA 2007 Q5 [15]}}